It depends on the value of X If we assume that the value of X is 22, then 22 + 4 = 26
This is easiest to answer by working out the probability of not getting such a license plate and subtracting that from 1. There are 10 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 10 different possible license plates (since there are 10 digits: 0-9 and 26 letters: A-Z). To not have any repeated digits or letters, there are: 10 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 9 possible license plates (since the two digits must be different and the seven letters must all be different). Meaning the probability of getting one of these is: (10 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 9)/(10 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 10) = (25 x 3 x 23 x 11 x 21 x 9)/(26 x 13 x 13 x 13 x 13 x 13) = 3586275/9653618 ⇒ probability of getting at least one repeating digit or number is: 1 - 3586275/9653618 = 6067343/9653618≈ 0.629
That depends - on how many letters are in the password - AND - if any letter can be repeated. For example... an eight-digit password has 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 = 208,827,064,576 possible combinations IF every letter can b repeated. If each letter can only be used once, then the formula is 26 x 25 x 24 x 23 x 22 x 21 x 20 x19 = 62,990,928,000 possible combinations.
22
1 x 572, 2 x 286, 4 x 143, 11 x 52, 13 x 44, 22 x 26
22 = 2 x 11, 64 = 26 so LCM = 11 x 26 = 11 x 64 = 704
It depends on the value of X If we assume that the value of X is 22, then 22 + 4 = 26
1404. 4 = 22 26 = 2 x 13 351 = 33 x 13 lcm = 22 x 33 x 13 = 1404
I used prime factorization. 2 x 11 = 22 and 2 x 13 = 26. That means that 2 x 11 x 13 will equal the LCM, 286.
121 is perfect three digit square palindrome. (11 x 11) So is 484 (22 x 22) and 676 (26 x 26)
The LCM of 3, 20, and 26 is 780. 3 = 3 x 1 20 = 2 x 2 x 5 = 22 x 5 26 = 2 x 13 Using the "highest exponent" method, you multiply 22 x 3 x 5 x 13 = 60 x 13 = 780
1 x 572, 2 x 286, 4 x 143, 11 x 52, 13 x 44, 22 x 26, 26 x 22, 44 x 13, 52 x 11, 143 x 4, 286 x 2, 572 x 1
To find the least common multiple (LCM) of 22, 26, and 351, first factorize each number into its prime factors: 22 = 2 x 11, 26 = 2 x 13, and 351 = 3 x 3 x 3 x 13. Then, identify the common and uncommon prime factors among the numbers. The LCM is the product of all the prime factors, including the highest power of each common factor. Therefore, the LCM of 22, 26, and 351 is 2 x 3 x 3 x 11 x 13 = 4298.
The prime factorization of 576 is: 26 x 32 = 576
This is easiest to answer by working out the probability of not getting such a license plate and subtracting that from 1. There are 10 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 10 different possible license plates (since there are 10 digits: 0-9 and 26 letters: A-Z). To not have any repeated digits or letters, there are: 10 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 9 possible license plates (since the two digits must be different and the seven letters must all be different). Meaning the probability of getting one of these is: (10 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 9)/(10 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 10) = (25 x 3 x 23 x 11 x 21 x 9)/(26 x 13 x 13 x 13 x 13 x 13) = 3586275/9653618 ⇒ probability of getting at least one repeating digit or number is: 1 - 3586275/9653618 = 6067343/9653618≈ 0.629
4. 24 = 23 x 3 36 = 22 x 32 64 = 26 hcf = 22 = 4
That depends - on how many letters are in the password - AND - if any letter can be repeated. For example... an eight-digit password has 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 = 208,827,064,576 possible combinations IF every letter can b repeated. If each letter can only be used once, then the formula is 26 x 25 x 24 x 23 x 22 x 21 x 20 x19 = 62,990,928,000 possible combinations.