2711 rounded to 2 significant digits is 2700
6.36*10^2
1,000 to 2 s.f., or 1,000 (2 s.f.) or 1,000.
236+710 = 946. Rounded to 2 significant digits, that is 950, rounded to one sd, it is 900.
0.00245 rounded to one significant figure is 0.002. The first significant figure is '2,' and all digits to the right are replaced with zeros. The leading zeros before the '2' do not count as significant figures.
2 of them are significant.
009999991 rounded to 2 significant digits is 1.0e7
2.99 rounded to three significant digits is 2.96 2.99 rounded to two significant digits is 3.0
3.2
Solution: Given, number = 0.4559 If a number only has 2 significant digits, the maximum significant digits it can be rounded to is 2 significant digits. The zeros before a non Zero digit are not significant. The since 9>5 it adds 1 to preceding one while rounding off. ⟹0.046. The original number, 0.4559, has 4 significant digits. Rounding this number to 2 significant digits gives us 0.46.
There are three rules that are used when rounding to a desired number of significant digits (figures): 1. All digits that are not zero, are significant 2. In a number that does not have a decimal point, all zeros between two non-zero digits are significant digits 3. In a number that has a decimal point, all zeros after the leftmost non-zero digit are significant Examples: 12345 rounded to 3 significant digits: 12300, or 1.23 x 104 12.345 rounded to 3 significant digits: 12.3, or 1.23 x 101 0.012345 rounded to 3 significant digits: 0.0123, or 1.23 x 10-2 0.012045 rounded to 3 significant digits: 0.0120, or 1.20 x 10-2 In the last example the zero after 2 is significant. That is the reason for keeping it in the result when rewriting it in powers of 10 notation.
6.36*10^2
1,000 to 2 s.f., or 1,000 (2 s.f.) or 1,000.
236+710 = 946. Rounded to 2 significant digits, that is 950, rounded to one sd, it is 900.
At least 1 and at most 7. It could be 3,999,999.9 rounded to 7 significant figures; It could be 3,999,999 rounded to 6 significant figures; It could be 4,000,015 rounded to 5 significant figures; It could be 4,000,429 rounded to 4 significant figures; It could be 3,999,999 rounded to 3 significant figures; It could be 4,049,999 rounded to 2 significant figures; It could be 4,492,467 rounded to 1 significant figure.
When rounding 1286 to 2 significant figures, you must consider the first two non-zero digits from the left. In this case, those digits are 1 and 2. The digit to the right of 2 (8) is greater than 5, so you round up. Therefore, 1286 rounded to 2 significant figures is 1300.
Just one. The trailing zeros are not significant. * * * * * Not true. Integers with trailing 0s are ambiguous. You cannot differentiate between 500o as a number rounded to the nearest thousand (1 significant digit), or the nearest hundred (2 sig digits), or the nearest ten (3 sig digits) or the nearest unit (4 sig digits).
5 significant digits because the 2 zeros are in between other significant digits.