x=2ab+7 x= 2(3)(5) +7 x=30+7 x=37
3 x 3 + 4 x 8 = 9 + 32 ...
As your question implies, the quadratic formula. You know your a,b and c already. X = - b (+/-) sqrt(b2- 4ac)/2a X = - 10 (+/-) sqrt[102 - 4(3)(8)]/2(3) X = - 10 (+/-) sqrt(100 - 96)/6 X = - 10 (+/-) sqrt(4)/6 X = [- 10 (+/-) 2]/6 --------------------------- X = - 4/3 and X = - 2
x equals 8
-8 + x = -3 x = -3 + 8 x = 5
2a x 3 = 24= 6a = 24(divide both sides by 6)a = 4
2a -3 means 2 times a minus 3 if a = 2 we have 2 x 2 - 3 = 4 - 3 = 1
x=2ab+7 x= 2(3)(5) +7 x=30+7 x=37
3 x 3 + 4 x 8 = 9 + 32 ...
if f(x) = 3x - 10, then whatever is put (substituted) for x in the "f(x)" bit is substituted for x in the "3x - 10" bit. Thus f(2a) = 3(2a) - 10 = 6a - 10.
As your question implies, the quadratic formula. You know your a,b and c already. X = - b (+/-) sqrt(b2- 4ac)/2a X = - 10 (+/-) sqrt[102 - 4(3)(8)]/2(3) X = - 10 (+/-) sqrt(100 - 96)/6 X = - 10 (+/-) sqrt(4)/6 X = [- 10 (+/-) 2]/6 --------------------------- X = - 4/3 and X = - 2
x equals 8
-5
-8 + x = -3 x = -3 + 8 x = 5
3a x 2a =24
3 + x = 8 x = 5
3