They are 1/2 the previous term and so the next term will be -32
1, 2, 4, 8, 16, 32, 64, 128.
The positive-integer factors of 128 are: 1, 2, 4, 8, 16, 32, 64, and 128
Well, you see, in this set of numbers it is very easy to tell that each number gets doubled
128, 512, ...
512 / 2 = 256 256 / 2 = 128 128 / 2 = 64 64 / 2 = 32 32 / 2 = 16 16 / 2 = 8 8 / 2 = 4 4 / 2 = 2 2 / 2 = 1
This sequence is called the doubling sequence.
They are 1/2 the previous term and so the next term will be -32
128. 1+1=2 2+2=4 4+4= 16 16+16= 32 32+32= 64 64+64 = 128 128+128 = 256 256+256 =512 512+512= 1024 Each time take the answer from the previous problem and double it to find the next number in the sequence.
7Because it is a logarithmic sequence:2^0 =1 so log2 1 = 02^3 = 8 so log2 8 = 32^5 = 32 so log2 32 = 52^7 = 128 so log2 128 = 7
24. It should be 32 which is double of 16
Start with your factor tree for each, it is simplest and sure way to not get a wrong answer. so for 32 8------4 4---2 2---2 2---2 LCM= 2*2*2*2*2 Now 128 32------4 2*2 We already know 32 is 2*2*2*2*2 so LCM is 2*2*2*2*2*2*2=128 so 128 is you LCM of 32 and 128
To find out how many times 48 goes into 128, you would divide 128 by 48. The quotient is 2 with a remainder of 32. This means that 48 goes into 128 twice, with 32 left over.
(sqrt(121)-8)**2/(32*4) (11-8)**2/(128)=9/128 (-11-8)**2/(128)=361/128 sqrt121-8**2/(32*4) 11-64/128=10.5 -11-64/128=-11.5 sqrt(121-8**2)/(32*4) sqrt(57)/128 -sqrt(57)/128 (sqrt(121)-8)**2/32*4 (11-8)**2/32*4=9/8 (-11-8)**2/32*4=361/8 sqrt121-8**2/32*4 11-64/32*4=3 -11-64/32*4=-19 sqrt(121-8**2)/32*4 sqrt(57)/8 -sqrt(57)/8
1, 2, 4, 8, 16, 32, 64, 128, -1, -2, -4, -8, -16, -32, -64, -128
The GCF of 96 and 128 is 32. The greatest common factor is the highest number that divides exactly into two or more numbers. 96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96 128: 1, 2, 4, 8, 16, 32, 64, 128 The GCF of 96 and 128 is 32.
The factors of 128 are: 1, 2, 4, 8, 16, 32, 64, and 128.The only prime factor of 128 is ' 2 '.