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Binary code of the value 1111?
10001010111 you get this by: each digit in a binary number is a power of 2 kind of like in the number '100' you have your 1's column, your 10's and your 100's 2^10 2^9 2^8 2^7 2^6 2^5 2^4 2^3 2^2 2^1 2^0 1024 512 256 128 64 32 16 8 4 2 1 the highest power of 2 that can go into 1111 is 2^10 which is 1024 so you go from the highest column and write a 1 1 now 1111-1024 gives you 87 left over the next highest that can go into 87 is 64 or 2^6 so you write a '0' under any number that doesn't match and a 1 under the 64 and you get 1024 512 256 128 64 32 16 8 4 2 1 1--------0----0----0---1 87-64 gives you 23 so do the same thing and you get: 1024 512 256 128 64 32 16 8 4 2 1 1--------0----0----0---1--0 --1 23-16 = 7 so 1024 512 256 128 64 32 16 8 4 2 1 1--------0 ---0---- 0 -1 - 0 --1 0 1 7-4=3 1024 512 256 128 64 32 16 8 4 2 1 1---------0---0-----0--1--0---1-0 1 1 3-2=1 1024 512 256 128 64 32 16 8 4 2 1 1 -------0 ----0 ---0 --1- 0 --1- 0 1 1 1 end result: 10001010111
How many times does 32 go into 122?
between 3 and 4 3 x 32 = 96 4 x 32 = 128 122/32 = 61/16 = 3.8125
How many different equations can be made with the numbers 0123?
A huge number. 0 + 1 + 2 = 3 0 + 2 + 1 = 3 1 + 0 + 2 = 3 1 + 2 + 0 = 3 2 + 0 + 1 = 3 2 + 1 + 0 = 3 -0 + 1 + 2 = 3 -0 + 2 + 1 = 3 1 - 0 + 2 = 31 + 2 - 0 = 32 - 0 + 1 = 32 + 1 - 0 = 3 0 - 1 + 3 = 2 0 + 3 - 1 = 2 -1 + 0 + 3 = 2 -1 + 3 + 0 = 2 3 + 0 - 1 = 2 3 - 1 + 0 = 2 -0 - 1 + 3 = 2-0 + 3 - 1 = 2-1 - 0 + 3 = 2-1 + 3 - 0 = 23 - 0 - 1 = 23 - 1 - 0 = 2 0 - 2 + 3 = 1 0 + 3 - 2 = 1 -2 + 0 + 3 = 1 -2 + 3 + 0 = 1 3 + 0 - 2 = 1 3 - 2 + 0 = 1 -0 - 2 + 3 = 1-0 + 3 - 2 = 1-2 - 0 + 3 = 1-2 + 3 - 0 = 13 - 0 - 2 = 13 - 2 - 0 = 1 1 + 2 - 3 = 0 1 - 3 + 2 = 0 2 + 1 - 3 = 0 2 - 3 + 1 = 0 -3 + 1 + 2 = 0 -3 + 2 + 1 = 0 For each of these equations there is a counterpart in which all signs have been switched. For example 0 + 1 + 2 = 3 gives -0 - 1 - 2 = -3and so on. Now, all of the above equations has three numbers on the left and one on the right. Each can be converted to others with two numbers on each side. For example:the equation 0 + 1 + 2 = 3 gives rise to0 + 1 = 3 - 20 + 1 = -2 + 30 + 2 = 3 - 10 + 2 = -1 + 31 + 2 = 3 - 01 + 2 = -0 + 3-0 + 1 = 3 - 2-0 + 1 = -2 + 3-0 + 2 = 3 - 1-0 + 2 = -1 + 31 + 2 = 3 + 01 + 2 = +0 + 3 As you can see, the number of equations is huge!
How much is 128 divided by 32?
4
What is the next number in the sequence 3 5 8 16 32 64 128?
256
