2 x 1.5 = 3
three
2 x 1.5 = 3
15-3 times 2 equals 15-6 equals 9.
The expression ( 2 \times \pi \times 15 ) calculates the circumference of a circle with a radius of 15 units. Using the approximate value of ( \pi ) as 3.14, the result is approximately ( 2 \times 3.14 \times 15 = 94.2 ). Therefore, ( 2 \times \pi \times 15 ) is approximately 94.2 units.
To express 225 in index form, we can factor it as (15^2) since (15 \times 15 = 225). The number 25 can be expressed as (5^2) because (5 \times 5 = 25). Therefore, (225 \times 25) can be rewritten as ((15^2) \times (5^2)). Converting 15 into its prime factors gives us ( (3 \times 5)^2 = 3^2 \times 5^2), so the full expression becomes (3^2 \times 5^2 \times 5^2 = 3^2 \times 5^4).
2 over 5 times 15 = 62/5 * 15= 30/5= 6
15/2*4 = 30
It is: 2/3 times 15 which is the same as 2/3 of 15 = 10
2 goes into 15 7 times with 1 remainder
30 because 2 times 15 is 30,3 times 10 is 30, and 15 times 2 is 30
15-3 times 2 equals 15-6 equals 9.
The expression ( 2 \times \pi \times 15 ) calculates the circumference of a circle with a radius of 15 units. Using the approximate value of ( \pi ) as 3.14, the result is approximately ( 2 \times 3.14 \times 15 = 94.2 ). Therefore, ( 2 \times \pi \times 15 ) is approximately 94.2 units.
To express 225 in index form, we can factor it as (15^2) since (15 \times 15 = 225). The number 25 can be expressed as (5^2) because (5 \times 5 = 25). Therefore, (225 \times 25) can be rewritten as ((15^2) \times (5^2)). Converting 15 into its prime factors gives us ( (3 \times 5)^2 = 3^2 \times 5^2), so the full expression becomes (3^2 \times 5^2 \times 5^2 = 3^2 \times 5^4).
15 can go into 6 times 0 times with a remainder of 6. (6 / 15 = 0.4)
2 over 5 times 15 = 62/5 * 15= 30/5= 6
2 times 1,000 = 2,000
2 goes into 15 7 times leaving a remainder of 1.
15/2*4 = 30
15 times with a remainder of 1 or 15.5 times