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Let us say that for each question, there are n multiple choices. If this is true and false, then n=2. The chance of getting a right answer is 1/n and wrong answer (n-1)/n. I will define p as getting a wrong answer one time (p = (n-1)/n so the probability of 20 wrong answers is p20. Now for n = 4, p=0.75 and the chance of 20 wrong answers in a row is: (0.75)20= 0.0032 or 0.32%.
percentage of 2 wrong out of 120 questions = 1.67%% rate:= 2/120 * 100%= 0.0167* 100%= 1.67%
10 questions with 2 answers each equals 20 possible answers. The combination of possible answers for the series would be much higher starting with they could be all a or all b then the first one a and the rest all b then the first two a the rest b etc
If you have 5 questions, each with only two possible answers, the total number of combinations is 2*2*2*2*2 or 2^5 = 32. If the questions are all multiple choice and independent (ie no filters), then the total number of combinations must be the multiple of the numbers of choices for the questions.
All but the simplest math questions are welcome and may be answered on WikiAnswers. (Simple calculation questions will be removed, eg. "what is 2+2".) Yes, wiki answers will help you to solve your math problems. Simple problems are solved directly, but for complex problems they will suggest related sites where you can get math questions with solutions.