24
there are four twos therefore the index number is 4 and two is because they are the same whole number
The answer to f x x-5 x plus 3 standard form is -6. This is a math problem.
exponential form: 2 x 2 x 2 x 2 x 2 = 2^5 standard form: 2^5 = 32
standard form: 2^5 = 32 exponential form: 2 x 2 x 2 x 2 x 2 = 2^5
As a polynomial in standard form, x plus 5x plus 2 is 6x + 2.
To write ( f(x) = (x - 2)(x - 6) ) in standard form, you need to expand the expression. Distributing the terms, you get ( f(x) = x^2 - 6x - 2x + 12 ), which simplifies to ( f(x) = x^2 - 8x + 12 ). Thus, the standard form of the function is ( f(x) = x^2 - 8x + 12 ).
The answer to f x x-5 x plus 3 standard form is -6. This is a math problem.
exponential form: 2 x 2 x 2 x 2 x 2 = 2^5 standard form: 2^5 = 32
standard form: 2^5 = 32 exponential form: 2 x 2 x 2 x 2 x 2 = 2^5
7.2*10^-2 is in standard form.
As a polynomial in standard form, x plus 5x plus 2 is 6x + 2.
Standard notation is 6,500,000,000 .Scientific notation is 6.5 x 109 .
To write ( f(x) = (x - 2)(x - 6) ) in standard form, you need to expand the expression. Distributing the terms, you get ( f(x) = x^2 - 6x - 2x + 12 ), which simplifies to ( f(x) = x^2 - 8x + 12 ). Thus, the standard form of the function is ( f(x) = x^2 - 8x + 12 ).
2 x 106
Either 0.002 or 2 X 10-3.
In a quadratic equation, the standard form is typically written as ( ax^2 + bx + c = 0 ). If the roots of the equation are 0 and 3, the equation can be derived from its factored form, which is ( (x - 0)(x - 3) = 0 ). Expanding this gives ( x^2 - 3x = 0 ), or in standard form, ( x^2 - 3x + 0 = 0 ). Thus, the quadratic equation in standard form is ( x^2 - 3x = 0 ).
The question i have to convert to standard form is -1/2(x-6)2
8.04 × 10-2 written in standard form is 0.0804