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How do you multiply two times pi times two?
2 x pi x 2 = 4 x pi
How was it determined that the tangent of pi divided by 4 is 1?
As tan(x)=sin(x)/cos(x) and sin(pi/4) = cos(pi/4) (= sqrt(2)/2) then tan(pi/4) = 1
What is the area of circles with a radius of 4 inches and with a diameter of 4 inches and with a circumference of 4 inches?
The area (A) of a circle is pi (about 3.14) times the square of the radius (r). The circumference (c) of a circle is pi times its diameter (d), or pi times twice its radius. Knowing that, we can investigate the three circles. If rcircle = 4, Areacircle = pi r2 = 3.14 x 42 = 3.14 x 16 = 50.27 sq. in. If dcircle = 4, Areacircle = pi (d/2)2 = 3.14 x (4/2)2 = 3.14 x (2)2 = 3.14 x 22 = 3.14 x 4 = 12.57 sq. in. If c - 4, Areacircle = pi (c/2 pi)2 = pi (42/4 pi2) = pi x 16/ 4 x pi2 = 16/ 4 x pi = 4/3.14 = 1.27 sq. in.
What is radius of circle with area of 4?
1.2 Area = pi X radius^2 So set Area = 4, and figure it out: 4 = pi X radius ^2 4/pi = radius^2
How do you solve 2cosx plus 2sinx equals sqrt2 for solutions between 0 and 2pi?
Not easily and, given the limitations of the pathetic browser that we have at our disposal, even less easy. But here goes:You are given that 2cosx + 2sinx = sqrt(2)Consider "collapsing" the left hand side into a single trig function:r*sin(x+a) = sqrt(2) ............................................. (A)that is r*cosxsina + r*sinxcosa = sqrt(2)comparing coefficients,rsina = 2 and rcosa = 2thensina = 2/r = cosaand since sin^2 + cos^2 = 1, you have r = 2*sqrt(2)also, rsina/rcosa = 2/2 = 1 = tana which implies that a = pi/4.Therefore, equation (A) is 2*sqrt(2)*sin(x+pi/4) = sqrt(2)so that sin(x+pi/4) = 1/2.......................................(B)Since 0
