(5a+8) - (2a+4) =3a +4 To do this, simply subtract like terms. 5a-2a=3a and 8-4=4
If We are looking for A, B and C If the first number is A then we know B = A+2 C = A+4 and 3A = B+C or 3A = (A+2) + (A+4) so 3A = 2A +6 3A - 2A = 6 A = 6 B= 8 C= 10
a + a + a - 2a = 3a - 2a = a
1
(3a+4)/12 - (5/3) = (2a-1)/2Multiply each side by 12:(3a+4) - (20) = 6 (2a-1)Eliminate the parentheses:3a + 4 - 20 = 12a -63a -16 = 12a -6Add 6 to each side:3a -10 = 12aSubtract 3a from each side:-10 = 9aDivide each side by 9:-10/9 = a
2a + 3a + 4 = 5a + 4
a = 3a + 4 0 = 2a + 4 2a = -4 a = -2
3a-2a = 1
(2a - 3)(3a - 4)
(5a+8) - (2a+4) =3a +4 To do this, simply subtract like terms. 5a-2a=3a and 8-4=4
3a + (3b - 2a) + 5b =3a + 3b - 2a + 5b =(3a - 2a) + (3b + 5b) =a + 8b
3a + 2a = 5a
since a=1a, 3a-1a=2a
If We are looking for A, B and C If the first number is A then we know B = A+2 C = A+4 and 3A = B+C or 3A = (A+2) + (A+4) so 3A = 2A +6 3A - 2A = 6 A = 6 B= 8 C= 10
It can be simplified to: 3a^2 +10a+7 or factored as (3a+7)(a+1)
(2a - 1)(3a + 4)
2a + 5a + 3a = 10a