The values of a and b are 7 and 18 or 18 and 7
b + b + b + 7 = 223b + 7 = 223b = 15b = 5
The answer is 144. The compound operator for (a) and (b) in each pair is a * (a+b). For 9 and 7, this is 9 x (9+7) = 9 x 16 = 144.
A^2 + b = 7 A + B^2 =11 -------------- A=2 and B=34(2^2) + 3 = 7 2 + 9(3^2) = 11
It is: b = -3
the answer is a
3
The values of a and b are 7 and 18 or 18 and 7
b + b + b + 7 = 223b + 7 = 223b = 15b = 5
The answer is 144. The compound operator for (a) and (b) in each pair is a * (a+b). For 9 and 7, this is 9 x (9+7) = 9 x 16 = 144.
A^2 + b = 7 A + B^2 =11 -------------- A=2 and B=34(2^2) + 3 = 7 2 + 9(3^2) = 11
It is: b = -3
To find this: You know (B+C) = 7. Therefore you know (A+A )= 21 - (B+C). Therefore 21-7 = 14. So now you know (A+A) = 14. So you divide (A+A)/2. This equals 7. Therefore A = 7.
If: 7+3b = 61 Then: b = 18
b=7
That depends what the values of k and b are.
b2 + 8x + 7. 7 and 1 add up to be 8 and multiply to be 7. So therefore, it would be factored as: (b+1)(b+7)