b^(2) + 8x + 7 Does NOT factor . Reason; you have two unknowns, viz. 'b' & 'x'.
However, if you means b^(2) + 8b + 7 . Herewe have one unknown viz. 'b'.
This factors to
( b + 7)(b + 1)
The expression (x^2 + 8x + 12) is a quadratic equation. It can be factored into ((x + 6)(x + 2)). This indicates that the solutions (or roots) of the equation (x^2 + 8x + 12 = 0) are (x = -6) and (x = -2).
(x - 6)(x - 2)
This is not factor-able.
8x squared
(x-3)(x-5) = 0
It can not be factored because its discriminant is less than zero
X2 - 8X + 15 = (X - 3)(X - 5)
x^2 +8x -9 is equivalent to (x+9)(x-1) when factored
(x + 4)(x +4) or (x + 4)squared
The expression (x^2 + 8x + 12) is a quadratic equation. It can be factored into ((x + 6)(x + 2)). This indicates that the solutions (or roots) of the equation (x^2 + 8x + 12 = 0) are (x = -6) and (x = -2).
18 + 8x + x = = 18 + 9x = 9(2 + x) which is the factored form of the expression.
(x - 6)(x - 2)
This is not factor-able.
8x2-39x+45 = (8x-15)(x-3) when factored
Y-8x plus 9y equals 10y-8x.
8x squared
(x-3)(x-5) = 0