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b^(2) + 8x + 7 Does NOT factor . Reason; you have two unknowns, viz. 'b' & 'x'.

However, if you means b^(2) + 8b + 7 . Herewe have one unknown viz. 'b'.

This factors to

( b + 7)(b + 1)

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lenpollock

Lvl 17
1mo ago

What else can I help you with?