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-4-3i
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∙ 10y ago
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What is the complete ionic equation for h2so4 plus cai2 equals caso4 plus 2hi?
2H+ + SO42- + Ca2+ + 2I- CaSO4 + 2H+ + 2I-
What is the angle between a equals 2i plus 2j-k and b equals 6i-3j plus 2k?
36.64
X2 plus x equals 3x-5?
x2 +x=3x-5 so x2 -2x+5=0 which does not factor ( over the real numbers) so you can either complete the square of use the quadratic equation to solve. Let's complete the square. (x-1)2 =-4 x-1= plus of minus 2i so x=1+2i or x=1-2i Now check it just as you would a real answer. 1+2i -1 is 2i and 2i squared is -4 as desired Now 1-2i-1 is -2i and (-2i) squared is -4 also. We know the answer is not real if we simply calculated the discriminant. b2 -4ac=4-4(5)<0 so there are no real answers as we found.
What does x equal in y equals x squared plus 4?
y equals x plus 4 when y equals 0 then x equals 2i i is the square root of negative 1
What is the solution set of the equation x2 minus 2x plus 5 equals 0?
Using the quadratic formula, you get the complex answers of 1 + 2i and 1 - 2i
What is the equivalent form of 10 plus 6i and 7 plus 2i?
10 + 6i and 7 + 2i = 10 + 6i + 7 + 2i = 17 + 8i
What is the answer to 5 plus 2i2-3i equals zero?
5 + 2 i 2 -3 i = 0(i + 1)(2i - 5) = 0(i + 1) = 0, so, i = -1and(2i - 5) = 0, so, i = 5/2i two values are: -1 and 5/2
What does 7i divided by 2 plus 2i equal?
1.75 + 1.75i7i/2 + 2i = 3.5i + 2i = 5.5i
The conjugate of the complex number 3 plus 2i is?
It is 3 minus 2i
What is the answer if you Find all the roots of the equation x4 - 2x3 plus 14x2 - 18x plus 45 0 given that 1 plus 2i is one of its roots.?
The four roots are:1 + 2i, 1 - 2i, 3i and -3i.
What is x to the 2nd power plus 4 equals 0?
x^2 plus 4 = 0x^2 = -4square root both sidesx = the square root of -4x = 2i
If x plus y equals -2 and xy equals 2 then what is x cubed plus y cubed?
x + y = -2 ∴ y = -2 - x xy = 2 ∴ x(-2 - x) = 2 ∴ -2x - x2 = 2 ∴ x2 + 2x + 2 = 0 ∴ x2 + 2x + 1 = -1 ∴ (x + 1)2 = -1 ∴ x + 1 = i ∴ x = i - 1 recall: y = - 2 - x ∴ y = - 2 - (i - 1) ∴ y = -2 - i + 1 ∴ y = - i - 1 ∴ x3 + y3 = (i - 1)3 + (- i - 1)3 = (i - 1)(i2 - 2i + 1) + (- i - 1)(i2 + 2i + 2) = i3 - 2i2 + i - i2 + 2i - 1 - i3 - 2i2 - 2i - i2 - 2i - 2 = i3 - i3 - 2i2 - i2 - 2i2 - i2 + i + 2i - 2i - 2i - 1 - 2 = -6i2 - i - 3 = 3 - i
