The answer is 21
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)
d/dx 2x2+3x+7=4x+3
2x2+13x+15 = (2x+3)(x+5)
The answer is 21
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)
2x2 equals 5
The GCF is 5x
It is a quadratic expression
2x2 + 3x + 1 = (x + 1)(2x + 1)
d/dx 2x2+3x+7=4x+3
2x2+13x+15 = (2x+3)(x+5)
If the original is 2x + 3x2 + 6 + 5x3, you should rearrange the terms in order of exponent:5x3 + 3x2 + 2x + 6
8 - 2x2 = x + 22 - 7Combine like terms on the right side:8 - 2x2 = x + 15Subtract 8 from each side:-2x2 = x + 7Add 2x2 to each side:0 = 2x2 + x + 7
2x2 + 11x + 15 = (x + 3)(2x + 5).