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Factor the polynomial in quadratic form 6y6 - 5y3 - 4?
Let y^(3) = x Hence y^(6) = x^(2) Substitute 6x^(2) - 5x - 4 Factor ( 2x + 1)(3x - 4) Substitute back 2y^(3) + 1 & 3y^(3) - 4
What is 6x-5y3 solved for x?
This is not solvable, as you have not equated it to any value. You have just given an 'Algebraic Expression'.
How many solutions does the system of equations have on 2x-10y 6 and x 5y3?
To determine the number of solutions for the system of equations given by (2x - 10y = 6) and (x = 5y + 3), we can substitute the expression for (x) from the second equation into the first equation. This results in a single equation in terms of (y). If this leads to a consistent solution (one value for (y)), there will be one unique solution for the system. If it leads to a contradiction or infinitely many solutions, that will change the outcome. Solving both equations reveals they intersect at one point, indicating there is exactly one solution.
-2x - 6 equals 2x plus 6?
-2x-6= -2x-6Another answer:-2x-6 = 2x+6-2x-2x = 6+6-4x = 12x = -3
Why does 2x-3 equals 2x-5 have no solution?
2x - 3 = 2x - 52x = 2x - 22x - 2x = -20 =/= -2Zero is not equal to -2 so the answer is no solution.
What is 6x-5y3 solved for x?
This is not solvable, as you have not equated it to any value. You have just given an 'Algebraic Expression'.
Factor the polynomial in quadratic form 6y6 - 5y3 - 4?
Let y^(3) = x Hence y^(6) = x^(2) Substitute 6x^(2) - 5x - 4 Factor ( 2x + 1)(3x - 4) Substitute back 2y^(3) + 1 & 3y^(3) - 4
Factor 5y3 - 125y?
5y^(3) - 125y => 5y(y^(2) - 25) => 5y(y^(2) - 5^(2)) => 5y(y- 5)(y + 5) Done !!!! Gully Factored!!!!!
What are the following vacuum tube types - 45 - 80 - 125A - 1C5 - 5Y3 - 5U4 - 12SA6?
45 - triode power amplifier 80 - fullwave rectifier 125A - - can't find data 1C5 - pentode power amplifier 5Y3 - equivalent to 80 5U4 - higher-rated version of 80/5y3 12SA6 - - can't find data - did you mean *12sa7* pentagrid converter
What is the LCM 5y to the third power and 25y to the sixth power?
LCM(5y3, 25y6) = 25y6
What was the differences between 5U4 5Y3 and Type 80 vacuum tubes?
Tube Socket ___ octal n 4pin
How many solutions does the system of equations have on 2x-10y 6 and x 5y3?
To determine the number of solutions for the system of equations given by (2x - 10y = 6) and (x = 5y + 3), we can substitute the expression for (x) from the second equation into the first equation. This results in a single equation in terms of (y). If this leads to a consistent solution (one value for (y)), there will be one unique solution for the system. If it leads to a contradiction or infinitely many solutions, that will change the outcome. Solving both equations reveals they intersect at one point, indicating there is exactly one solution.
Why is 2x cubed different from 2x times 2x times 2x?
2X * 2X * 2X = 8X^3 2X^3 is saying 2*( X * X * X) = 2X^3
What is -2x plus 2x?
It is 2x+(-2x) = 0
How do you do 2x times 2x?
2x * 2x (2*2=4) therefore, 2x*2x equals 4x2.
-2x - 6 equals 2x plus 6?
-2x-6= -2x-6Another answer:-2x-6 = 2x+6-2x-2x = 6+6-4x = 12x = -3
2x +2x + 2x=?
6x
