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5y(y - 5)(y + 5)

Q: Factor 5y3 - 125y

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factor pair = 1512,1 factor pair = 756,2 factor pair = 504,3 factor pair = 378,4 factor pair = 252,6 factor pair = 216,7 factor pair = 189,8 factor pair = 168,9 factor pair = 126,12 factor pair = 108,14 factor pair = 84,18 factor pair = 72,21 factor pair = 63,24 factor pair = 56,27 factor pair = 54,28 factor pair = 42,36

Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals", "squared", "cubed". The answer is probably 3, the highest power of y in the expression, but it depends on what symbol is before "6y".

I usually start from the bottom - is 2 a factor, yes indeed. Then start over. Is 2 a factor, yes. Start over. Is 2 a factor, yes. Is 2 a factor, no. Is 3 a factor, no. is 4 a factor, no. Done.2, 2, 2, 5

The following are the factor pairs of 950 factor pair = 950,1 factor pair = 475,2 factor pair = 190,5 factor pair = 95,10 factor pair = 50,19 factor pair = 38,25

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6y6-5y3-4

x = 5y3/6

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LCM(5y3, 25y6) = 25y6

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y to the six is common, so it becomes y^3(y^3 - 125). Then we use difference of cubes ((a-b)(a^2 - 2ab + b^2)), so it becomes y^3(y-5)(y^2 + 5y + 25). Since we cannot factor out that last quadratic part, this concludes the factoring process and we end up with that last line as our answer.

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Just to clarify: (12x4y2)/(10x3y5). Subtract the exponents of x: 4-3 = 1. And y exponents: 2-5 = -3. Then 12/10 simplifies to 6/5, so we have (6x)/(5y3)

(1/2y3)2(.5y3)2Multiply each term's exponent by 2 (remember that .5 = .51).52y(6).25y6 or 1/4y6

Y³-4y²-12y = y(y - 6)(y + 2) 3x³+30x²+75x = 3x(x + 5)2 5yto5-80y³ = 5y3(y + 4)(y - 4) 24to5-18y³ = 6y3(4y2 - 3) 25x to the 6th - 64 = (5x3 + 8)(5x3 - 8) 27xt³+343 = (3x + 7)(9x2 - 21x + 49) X³-64 = (x - 4)(x2 + 4x + 16)

4x + y53 is an expression. Thanks to the rubbish browser used by this site for posting question, most mathematical symbols have been stripped out. There is, therefore, no equality not inequality sign and so there is nothing which can be solved.