To solve the equation (2x + 3y = 12) for (x), first, isolate (2x) by subtracting (3y) from both sides, giving (2x = 12 - 3y). Then, divide both sides by 2 to solve for (x): (x = \frac{12 - 3y}{2}). Simplifying further, (x = 6 - \frac{3y}{2}).
2x-11
-2x plus 3y equals 1
Y=4-(2x/3)
2x + 3y = 12 x = 1.45, so 2 * 1.45 + 3y = 12 2.9 + 3y = 12 3y = 12 - 2.9 = 9.1 y = 9.1/3 = 3.0333... or 91/30 or 3 1/30.
x - 3y = -3: multiply by -2 giving -2x + 6y = 6, but -2x + 6y = 12 so we have a problem! Misprint?
2x-11
-2x plus 3y equals 1
Y=4-(2x/3)
2x + 3y = 12 x = 1.45, so 2 * 1.45 + 3y = 12 2.9 + 3y = 12 3y = 12 - 2.9 = 9.1 y = 9.1/3 = 3.0333... or 91/30 or 3 1/30.
x - 3y = -3: multiply by -2 giving -2x + 6y = 6, but -2x + 6y = 12 so we have a problem! Misprint?
(2,7)
2x plus 3y
2x + 3y = 17 3x + 4y = 24 (2x + 3x) + (3y + 4y) = (17 + 24) 5x + 7y = 41
2x-3y=13
They are parallel lines.
How do you add 2x plus 3y equals 18 in 5x-y equals 11
x = 3 and y = 2 (3,2)