x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
5x + x - 6x + 2x = 2x
x4+6x3-2x-12 (x3-2)(x+6)
4x3+10x2-6x 2x(2x2+5x-3) 2x(2x-1)(x+3)
To solve this equation, we will first subtract 2x from each side:8x=2x+6 (8x minus 2x=6x)6x=6Now, to isolate x, we must divide out the 6:6x=6 (6x divided by 6= x)x=1If 8x=2x+6, x=1
x + 2x + 6x = 9x
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
5x + x - 6x + 2x = 2x
x4+6x3-2x-12 (x3-2)(x+6)
4x3+10x2-6x 2x(2x2+5x-3) 2x(2x-1)(x+3)
To solve this equation, we will first subtract 2x from each side:8x=2x+6 (8x minus 2x=6x)6x=6Now, to isolate x, we must divide out the 6:6x=6 (6x divided by 6= x)x=1If 8x=2x+6, x=1
4x + 2 +2x - 6 = 0 6x -4 = 0 +4 +4 6x=4 x= 4/6 x=2/3
Numerator = (x + 4)*(x + 3) Denominator = (2x - 1)*(x + 3) Calcelling out the common factor, (x + 3), the answer is (x + 4) divided by (2x - 1) provided x ≠0.5
6x with 3 over the x, because that is how many x's there are.
16 + 6x - x2 = 16 + 8x - 2x - x2 = 8*(2 + x) - x*(2 + x) = (8 - x)*(2 + x)
this is the same as 6x - 2 = 6x - 2! There are an infinite number of possibilities for "x".
In order.6X + 4X = 10X10X - 2X = 8X8X + (1)X = 9X9X-------final answer