2x + 5x - 1 = 9x 7x - 1 = 9x -1 = 9x - 7x -1 = 2x -1/2=x
2x2 - 9x + 10 = 2x2 - 4x - 5x + 10 = 2x(x - 2) - 5(x - 2) = (x - 2)(2x - 5)
2x2 + 9x + 10
X= -2
2x2 + 10 - 9x = 0 or 2x2 - 9x + 10 = 0 So (x - 2)*(2x - 5) = 0
2x + 5x - 1 = 9x 7x - 1 = 9x -1 = 9x - 7x -1 = 2x -1/2=x
2x2 - 9x + 10 = 2x2 - 4x - 5x + 10 = 2x(x - 2) - 5(x - 2) = (x - 2)(2x - 5)
2x2 + 9x + 10
X= -2
2x2 + 10 - 9x = 0 or 2x2 - 9x + 10 = 0 So (x - 2)*(2x - 5) = 0
this is the same as 6x - 2 = 6x - 2! There are an infinite number of possibilities for "x".
9x=2x+14 subtract 2x from both sides you have 7x = 14 left. divide each side by 7 x=2
If you mean: 2x^2 +9x +7 then it is (2x+7)(x+1) when factored
2x^3-3x^2-11x+7x+32x^2-9x+16 R -41x+3 l 2x^3-3x^2-11x+7-(2x^3+6x^2)-9x^2-11x+7-(-9x^2-27x)16x+7-(16x+48)-412x^2-9x+16-[41/(x+3)]
Use the quadratic formula. x = -4.265564 or -0.234436
2x2 + 10 = 9x 2x2 - 9x + 10 = 0 (x - 2)(2x - 5) = 0
There is no solution to: 4(2x + 2) + 12 > 1004(2x + 2) + 12 > 100 For 4(2x + 2) + 12 > 1004(2x + 2) + 12 to have a solution x < -1 which makes 1004(2x + 2) + 12 < 12, BUT 1004(2x + 2) + 12 is supposed to be greater than 100. Perhaps there is a missing operator in the digits of 1004?