2x^3-3x^2-11x+7
x+3
2x^2-9x+16 R -41
x+3 l 2x^3-3x^2-11x+7
-(2x^3+6x^2)
-9x^2-11x+7
-(-9x^2-27x)
16x+7
-(16x+48)
-41
2x^2-9x+16-[41/(x+3)]
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your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
Provided that x- 2 is not zero: 2x3 + x2 - 13x + 6 = 2x3 - 4x2 + 5x2 - 10x - 3x + 6 = 2x2*(x - 2) + 5x*(x - 2) - 3*(x - 2) = (x - 2)*(2x2 + 5x - 3) Therefore, (2x3 + x2 - 13x + 6)/(x - 2) = (x - 2)*(2x2 + 5x - 3)/(x - 2) = 2x2 + 5x - 3 If x = 2 so that x - 2 = 0, then the expression is not defined.
-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
whats the answer for -2x^3+2^2+12x
Fifth degree - the highest power of x that appears.