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What is 2x3 plus 11x equals 6x?
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
What is 2x cubed plus x squared minus 13x plus 6 divided by x minus 2 giving reasons why your answer is correct?
Provided that x- 2 is not zero: 2x3 + x2 - 13x + 6 = 2x3 - 4x2 + 5x2 - 10x - 3x + 6 = 2x2*(x - 2) + 5x*(x - 2) - 3*(x - 2) = (x - 2)*(2x2 + 5x - 3) Therefore, (2x3 + x2 - 13x + 6)/(x - 2) = (x - 2)*(2x2 + 5x - 3)/(x - 2) = 2x2 + 5x - 3 If x = 2 so that x - 2 = 0, then the expression is not defined.
What is the factorization of the trinomial -2x3 plus 2x2 plus 12x?
-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
-2x3 plus 2x2 plus 12x?
whats the answer for -2x^3+2^2+12x
What is the degree of 6x5 - 4x2 plus 2x3 - 3 plus x?
Fifth degree - the highest power of x that appears.
What is 2x3 plus 11x equals 6x?
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
What is the quotient when the polynomial 2x4 minus 9x3 plus 13x2 minus 15x plus 9 is divided by the polynomial x minus 3?
2x^3 - 3x^2 + 4x - 3
Quotient and remainder of 3X4 plus 2X3 minus X2 minus x minus 6 divided by X2 plus 1?
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
2x3 plus 11x2 plus 11x-19 divided by x plus 3?
It is still uncertain, from this writing whether 'x+3' is dividing just the '11X-19' aspect, or whether it is meant to be dividing all of the preceding. Normally, as it is written, it means the former: (a) Multiplication, in this problem, is done first, following the BODMAS rule: 2X3=6; 11X2=22; and 11X-19=-209 So, the problem now reads: 6+22+-209/(x+3) ANS = 28-209/(x+3) (b) If we assume the intended meaning is to divide the whole lot by x+3, in which case the original question should finish by saying, "all divided by x plus 3", the problem is set out such: [2X3+11X2+11X-19]/(x+3) = [6+22-209]/(x+3) =[28-209]/(x+3) ANS = 181/(x+3)
How do you solve this 2x3 - 11x2 plus 24x - 18 diveded by 2x - 3?
The real equation got messed up when I posted it, the real equation is this: 2x^3 - 11x^2 + 24x - 18 divided by 2x - 3 ^ = to the 3rd and 2nd power.
What is 2x squared plus 5x minus 3 multiplied by plus x minus 2?
(x-2)*(2x2+5x-3) Multiply out the brackets term by term taking care with the minus terms:- 2x3-4x2+5x2-10x-3x+6 Collect like terms:- Answer: 2x3+x2-13x+6
X4-2x3 plus 2x2 plus x plus 4 divided by x2 plus x plus 1 solutions?
(x4 - 2x3 + 2x2 + x + 4) / (x2 + x + 1)You can work this out using long division:x2 - 3x + 4___________________________x2 + x + 1 ) x4 - 2x3 + 2x2 + x + 4x4 + x3 + x2-3x3 + x2 + x-3x3 - 3x2 - 3x4x2 + 4x + 44x2 + 4x + 40R∴ x4 - 2x3 + 2x2 + x + 4 = (x2 + x + 1)(x2 - 3x + 4)
What is 2x cubed plus x squared minus 13x plus 6 divided by x minus 2 giving reasons why your answer is correct?
Provided that x- 2 is not zero: 2x3 + x2 - 13x + 6 = 2x3 - 4x2 + 5x2 - 10x - 3x + 6 = 2x2*(x - 2) + 5x*(x - 2) - 3*(x - 2) = (x - 2)*(2x2 + 5x - 3) Therefore, (2x3 + x2 - 13x + 6)/(x - 2) = (x - 2)*(2x2 + 5x - 3)/(x - 2) = 2x2 + 5x - 3 If x = 2 so that x - 2 = 0, then the expression is not defined.
Factor 4x5 plus 6x3 plus 6x2 plus 9?
Rearrange: 4x5 + 6x2 + 6x3 + 9 Group: 2x2 (2x3 + 3) + 3 (2x3 + 3) Simplify to get your answer: (2x2 + 3) (2x3 + 3)
What is 7 plus 2x3?
13
What is the remainder when 2x4 plus 5x3 - 17x2 - 5 is divided by x plus 3?
Quotient: 2x3-x2-14x+42 Remainder: -131 over (x+3)
2x3 - 7 plus 5x2 - x3 plus 3x - x3?
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
