It is, as stated, 2x2 + x - 1 = 0. That is the quadratic form.
It is a quadratic equation in the form of y2-4y-5 = 0 and will have two solutions: When factorised: (y-5)(y+1) = 0 Therefore: y = 5 or y = -1
No, it is the discriminant of a quadratic equation.
Merge the equations together and form a quadratic equation in terms of x:- 3x2-20x+28 = 0 (3x-14)(x-2) = 0 x = 14/3 or x = 2 So when x = 14/3 then y = -13/3 and when x = 2 then y = 1
ax2+bx+c = 0 is the general form of a quadratic equation which normally has two solutions
(4+x) (2x-3)
It is, as stated, x2 - 5x + 25/4 = 0
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The Quadratic Formula song: (my grade saver) To the tune of the jack in the box song X equals negative B plus or minus square root of B squared minus 4AC all over 2A :)
It is a quadratic equation in the form of y2-4y-5 = 0 and will have two solutions: When factorised: (y-5)(y+1) = 0 Therefore: y = 5 or y = -1
No, it is the discriminant of a quadratic equation.
Using the quadratic formula-- ((negative b plus or minus the square root of b squared minus 4ac) divided by (2a)) you'll want to google that so you can see it in numerical form. a, b, and c are the coefficiants of your three terms ( 2 is a, -5 is b, and 2 is c) The answer is (x-2)(2x-1).
Merge the equations together and form a quadratic equation in terms of x:- 3x2-20x+28 = 0 (3x-14)(x-2) = 0 x = 14/3 or x = 2 So when x = 14/3 then y = -13/3 and when x = 2 then y = 1
Quadratic equations are called quadratic because quadratus is Latin for ''square'';in the leading term the variable is squared. also...it is form of ax^2+bx+c=0
ax2+bx+c = 0 is the general form of a quadratic equation which normally has two solutions
x^2 - y^2 - 4 is in its simplest form.
(4x-8)(2x+2)
(4+x) (2x-3)