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It is a quadratic equation in the form of y2-4y-5 = 0 and will have two solutions:

When factorised:

(y-5)(y+1) = 0

Therefore: y = 5 or y = -1

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Q: What is y squared minus 4y minus 5?
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What are the points of intersection when the line x -y equals 2 crosses the curve x squared - 4y squared equals 5?

If: x -y = 2 then x^2 = y^2 +4y +4 If: x^2 -4y^2 = 5 then x^2 = 4y^2 +5 So: 4y^2 +5 = y^2 +4y +4 Transposing terms: 3y^2 -4y +1 = 0 Factorizing the above: (3y -1)(y -1) = 0 meaning y = 1/3 or y = 1 Substitution into the original linear equation intersections are at: (7/3, 1/3) and (3, 1)


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