(√4x^2)(√36x)=2x(6√x)=12x√x
32 - 121 - 64 = 36x => -153 = 36x so that x = -4.25
x=-12
x = 4
x + 36 = 82x = 82 - 36x = 46
√36x^3 = √(6^2)(x^2)x =6x√x
32 - 121 - 64 = 36x => -153 = 36x so that x = -4.25
(√4x^2)(√36x)=2x(6√x)=12x√x
32 - 121 - 64 = 36x => -153 = 36x so that x = -4.25
36x+10
x=-12
52x - 7 = 33 - 36x + 4 52x + 36x = 33 + 7 + 4 88x = 44 x = 1/2
x = 4
x + 36 = 82x = 82 - 36x = 46
3x2 + 36x + 81 = 3(x2 + 12x + 27) = 3(x + 3)(x + 9), which are its prime factors; or, if you prefer, 3x2 + 36x + 81 = (3x + 9)(x + 9), which is also accurate. You may easily verify these results by multiplying back.
10x2 - 64 = 36x + 6x2Subtract 6x2 from both sides:4x2 - 64 = 36xSubtract 36x from both sides:4x2 - 36x - 64 = 0Divide everything by 4:x2 - 9x - 16 = 0Use the quadratic formula:x = (9±√(92-4(-16)))/(2)x = (9-√(145))/2 or x = (9+√(145))/2
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