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(√4x^2)(√36x)=2x(6√x)=12x√x

Q: What is the answer to the square root of 4x2 times the square root of 36x?

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4x2-36x+81 (2x-9)(2x-9)

In real numbers there is no square root of -4x2 However, when using complex numbers where √-1 = i, then: √-4x2 = 2xi If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving: y2 - 4x2 = (y + 2x)(y - 2x)

The expression is likely 4x2 - 36x +81 which is the same as (2x - 9)(2x - 9) or (2x - 9)2

(2x - 9)(2x - 9)

10x2 - 64 = 36x + 6x2Subtract 6x2 from both sides:4x2 - 64 = 36xSubtract 36x from both sides:4x2 - 36x - 64 = 0Divide everything by 4:x2 - 9x - 16 = 0Use the quadratic formula:x = (9Â±âˆš(92-4(-16)))/(2)x = (9-âˆš(145))/2 or x = (9+âˆš(145))/2

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4x2-36x+81 (2x-9)(2x-9)

81.

In real numbers there is no square root of -4x2 However, when using complex numbers where √-1 = i, then: √-4x2 = 2xi If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving: y2 - 4x2 = (y + 2x)(y - 2x)

4x2 - 36x + 81 = 4x2 - 18x - 18x +81 = 2x(2x - 9) - 9(2x - 9) = (2x - 9)2

The expression is likely 4x2 - 36x +81 which is the same as (2x - 9)(2x - 9) or (2x - 9)2

(2x - 9)(2x - 9)

x = square root of 3.

10x2 - 64 = 36x + 6x2Subtract 6x2 from both sides:4x2 - 64 = 36xSubtract 36x from both sides:4x2 - 36x - 64 = 0Divide everything by 4:x2 - 9x - 16 = 0Use the quadratic formula:x = (9Â±âˆš(92-4(-16)))/(2)x = (9-âˆš(145))/2 or x = (9+âˆš(145))/2

Only if the term under the radical (square root sign) can be simplified to a rational expression. For example, âˆš(4x2).

(2x - i)(2x + i)where i is the square root of negative 1.x = 0.5i, -0.5i

Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)

b. -4x2+20 = 4x2 = 4-20x2 = -16x = -4Note that -42 = -16 but (-4)2 in brackets = 16