3-y6 = -3
just solve for x. 1) add 3y6 to both sides 2x=3y6 2) divide both sides by 2 to get x by itself: x=3y6/2
There are infinitely many in each of the two curves/lines.
sqrt(45y12) = sqrt(5*9y12) = sqrt(5)*sqrt(9y12) = sqrt(5)*3y6
If you mean: 2x+3y = 6 then the coordinates are (3, 0) and (0, 2) giving the triangle an area of 3 square units
No, the expression ( x^2 + 3y^6 ) is not a linear function. A linear function is one that can be written in the form ( ax + by = c ), where ( a ), ( b ), and ( c ) are constants, and the variables ( x ) and ( y ) are to the first power. In this case, both ( x^2 ) and ( 3y^6 ) involve variables raised to powers greater than one, indicating that the function is nonlinear.
just solve for x. 1) add 3y6 to both sides 2x=3y6 2) divide both sides by 2 to get x by itself: x=3y6/2
SR-250
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you mean -x + 3y + 6 = 0? y = x/3 - 2
There are infinitely many in each of the two curves/lines.
The VIN number 3Y6-111910 corresponds to a model of the Yugo car, specifically the Yugo GV. The first character "3" indicates the vehicle's country of origin, while the subsequent characters help identify the manufacturer and specific model. To obtain detailed specifications or more precise information, a full VIN decode would be necessary.
I'm sorry I cant graph this, because I don't have a way to show you. But, you can look on google.com, and type in 'graphing calculator'. This should help you.
If you mean: -x+3y = 6 and x+3y = 18 then by substitution x = 6 and y = 4
sqrt(45y12) = sqrt(5*9y12) = sqrt(5)*sqrt(9y12) = sqrt(5)*3y6
If you mean: 2x+3y = 6 then the coordinates are (3, 0) and (0, 2) giving the triangle an area of 3 square units
If you mean: 2x-3y = 6 and 4x-6y = 1 then it works out that the equations are parallel to each other because both of their slopes are 2/3
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