310
31 x 10 = 310
279
10 with 1 remaining 31 - 1 = 30 = 3 x 10
8 times with a remainder of 10
31 billion can be expressed in scientific notation as (3.1 \times 10^{10}). This is achieved by moving the decimal point in 31 to the right, which shifts the exponent of 10 to 10, as there are ten places from 3.1 to 31 billion.
31
2 to the second power times 31
41
31 x 10 = 310
3 goes into 31 10 times with remainder 1.
9.11 x 10-31 = 0.000000000000000000000000000000911
1836 times the mass of an electronSo how do you calculate '1836 times the mass of a proton' ?Mass of proton = 1.673 x 10-27 or (10 to the power of negative 27)Mass of electron = 9.109 x 10-31 or (10 to the power of negative 31)Simply by dividing the largest mass (of protons) by the smallest mass (electrons):(1.67262 . 10-27) / (9.10939 . 10-31) = [1.67262 /9.10939] . [10(-27)-(-31)] =0.1836 . 10+4 = 1836
it is 2,790
279
10 with 1 remaining 31 - 1 = 30 = 3 x 10
31 x 10 = 310 Therefore there is only a single zero.
3 squared times 2 times 10 32*2*10 = 9*2*10 = 180