1/3
There are infinitely many pairs of number. Let A be any number and let B = A + 333333.Then B - A = A + 333333 - A = 333333.Since The choice of A is arbitrary so A could be any one of infinitely many numbers. Therefore, there are infinitely many solutions.
To convert the decimal 0.4615384615 to an improper fraction, we first note that this is a repeating decimal with the repeating pattern 461538. To convert this to a fraction, we can set x = 0.4615384615 and multiply by a power of 10 to shift the decimal point: 1000000x = 461538.4615. Subtracting the original equation from this new one gives 999999x = 461538, so x = 461538/999999. This fraction can be simplified by finding the greatest common divisor of 461538 and 999999, which is 3, resulting in the improper fraction 153846/333333.
.333333 is not an integer. An integer is a whole number like 1, 2, 3...
As given it is an integer. However, if redrafted as 0.634920634920634... at every Which is a recurring decimal to infinity. This decimal recurs at every sixth digit. So we say Let P = 0.634920634920634... 1000000P = 634920.634920634... Subtract 999999P = 634920 . 0 Note the decimals subtract to zero. P = 634920/999999 Cancel down by '3' 211640/333333 The answer!!!!! Subtract
1/3
Yes because it can be expressed as a fraction in the form of 1/3
The fraction 1/3 in decimal form is .3 repeating (.333333...)
EitherAs a percent: 33.3333...%orAs a decimal: .333333...orAs a fraction: 1/3
There are infinitely many pairs of number. Let A be any number and let B = A + 333333.Then B - A = A + 333333 - A = 333333.Since The choice of A is arbitrary so A could be any one of infinitely many numbers. Therefore, there are infinitely many solutions.
3,3,7,11,13, and 37
333333
little fishiessss <333333 little fishiessss <333333 i am afraid...? anyway, little cleaner fish, i forgot the name.
Amanda love and cuddle with <333333
.333333 (repeating)
333333
Follow @Megnasty_ <333333