(x - 3x - 6) / 6 = (3x + 2) / 3 ∴3x - 9x - 18 = 18x + 12 ∴3x - 9x - 18x = 12 - 18 ∴-24x = -6 ∴ x = 1/4
-9x+6=y (swap over +6 and y) -9x-y=-6 (when u move numbers or letters over d equal sign u need 2 change signs) 9x+y=6 (chaned all signs) y= 6-9 y= -3 9x+y=6 9x+-3=6 9x=6+3 9x=9 x=9(divided by) 9 x=1 9x+y=6 9+-3=6 So the ordered pair is (1,-3)
- 9X + 3Y = - 6 add 9X to each side 3Y = 9X - 6 divide all by 3 Y = 3X - 2
x^2-9x+18=(x-6)(x-3)
9x+6 = 7x+18 9x-7x = 18-6 2x = 12 x = 6
(x - 3x - 6) / 6 = (3x + 2) / 3 ∴3x - 9x - 18 = 18x + 12 ∴3x - 9x - 18x = 12 - 18 ∴-24x = -6 ∴ x = 1/4
-9x+6=y (swap over +6 and y) -9x-y=-6 (when u move numbers or letters over d equal sign u need 2 change signs) 9x+y=6 (chaned all signs) y= 6-9 y= -3 9x+y=6 9x+-3=6 9x=6+3 9x=9 x=9(divided by) 9 x=1 9x+y=6 9+-3=6 So the ordered pair is (1,-3)
9x+6 = 6x+15 9x-6x = 15-6 3x = 9 x = 3
2x + 6 + 9x = 39 11x + 6 = 39 11x = 39 - 6 11x = 33 x = 3
- 9X + 3Y = - 6 add 9X to each side 3Y = 9X - 6 divide all by 3 Y = 3X - 2
x2+9x+18 find factors of 18 that add up to 9, in this case 6&3 (x+6)(x+3)
10x+3 < 9x-6 (subtract 9x from both sides to give..) if and only if x+3 < -6 (subtract 3 from both sides to give ..) if and only if x < -9
x2-9x+18 = (x-3)(x-6) when factorised
x^2-9x+18=(x-6)(x-3)
9x+6 = 7x+18 9x-7x = 18-6 2x = 12 x = 6
12x + 6=9x + 27 12x-9x + 6=9x - 9x + 27 subtract 9x from both sides. 3x + 6 = 27 simplify 3x + 6 - 6=27 - 6 subtract 6 from both sides. 3x=21 simplify 3x/3=21/3 divide both sides by 3 x=7 simplify 12(7) + 6=>84+6=>90 9(7) + 27=>63+27=>90 It checks out!
3(x + 1)(x + 2)