Asuming you ment The Factor of x^2+9x+18 the answer is (x+3)(x+6) Asuming you ment The Factor of x^2+9x+18 the answer is (x+3)(x+6)
x2-9x = x(x-9)
x2 - y2 + 9x - 9y =(x2 + 9x) - (y2 + 9y) =x(x + 9) - y(y + 9)================================Another way to go after it:x2 - y2 + 9x - 9y =(x2 - y2) + 9x - 9y =(x + y) (x - y) + 9 (x - y) =(x + y + 9) (x - y)
The factors are (x + 6) and (x - 3)
x - x2 - 9x + 14 = 0 ; whence, x2 + 8x = 14 , x2 + 8x + 16 = 30 , and x + 4 = ±√30 . Therefore, x = ±√30 - 4 .
x2 - 9x + 18 = (x - 3)(x - 6)
x^2-9x+18=(x-6)(x-3)
x2-9x+18 = (x-3)(x-6) when factorised
(x - 6)(x - 3)
Asuming you ment The Factor of x^2+9x+18 the answer is (x+3)(x+6) Asuming you ment The Factor of x^2+9x+18 the answer is (x+3)(x+6)
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
This is the equation we want to factorize: x2 - 11x + 18 And there are two answers (the numbers are the same, but +/- signs are inverted): 1. (x - 2)(x - 9) = x2 - 9x - 2x -(-18) = x2 - 11x + 18 2. (-x + 2)(-x +9) = x2 -9x -2x + 18 = x2 - 11x + 18
x2-9x = x(x-9)
(x-9)(x+9)
3(x2 + 3x + 1)
(x+7)(x+2)
x2 - 9x + 8 = (x-1)(x-8)