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p^2-3
It is an inequality than can be solved for p: 5 ≥ p - 3 → p - 3 ≤ 5 → p ≤ 8 So any value less than, or equal to, 8 will do for p.
All points less than 3 distant from point 'P' comprise a circle, centered at 'P', with a radius of 3, but NOT including the line that is the circumference of the circle.
p-2
51 = 3*17