3 signs of madness
frequency [Hz] = velocity[m/s] / wavelength [m] frequency [Hz] = 24 [m/s] / 3 [m] frequency = 8 [Hz]
300000000 m/s = 3 × 10^8 m/s c ≈ 2.99792458 m/s = 2.99792458 × 10^8 m/s which is usually rounded to 3 × 10^8 m/s
Time. 3 milliseconds
Vf = V0 + at --> 0 = (8.5 m/s) - (5.3 m/s²)t -> t = (8.5 m/s)/(5.3 m/s²) = 1.60377 s
To determine which greyhound is faster, we can calculate their speeds. Fluffy travels 15 m in 2 seconds, giving a speed of 7.5 m/s (15 m ÷ 2 s). Tiberius travels 20 m in 3 seconds, resulting in a speed of approximately 6.67 m/s (20 m ÷ 3 s). Therefore, Fluffy is the faster greyhound.
180 IS THE M S WITH 3 D
frequency [Hz] = velocity[m/s] / wavelength [m] frequency [Hz] = 24 [m/s] / 3 [m] frequency = 8 [Hz]
300000000 m/s = 3 × 10^8 m/s c ≈ 2.99792458 m/s = 2.99792458 × 10^8 m/s which is usually rounded to 3 × 10^8 m/s
The acceleration of the skater is 2 m/s². This is calculated by taking the final velocity (9 m/s) minus the initial velocity (3 m/s), and then dividing by the time (3 s).
A car is a motor vehicle with wheels, used for transportation. Acceleration is the rate at which an object changes its velocity. In this case, the car increases its speed from 5 m/s to 20 m/s over 3 seconds, resulting in an acceleration of (20 m/s - 5 m/s) / 3 s = 5 m/s².
The car's acceleration is 5 m/s^2. This is calculated by dividing the change in velocity (20 m/s - 5 m/s = 15 m/s) by the time it took to change (3 s).
To determine the rate of the reaction that follows the rate law rate = k[A]^m[B]^n, where k = 3 M^(-2) s^(-1), [A] = 2 M, and [B] = 3 M, we first need to substitute these values into the rate law. Given that m = 2 and n = 3, the rate can be calculated as follows: Rate = k[A]^m[B]^n = 3 M^(-2) s^(-1) * (2 M)^2 * (3 M)^3 = 3 * 4 * 27 = 324 M/s. Thus, the rate of the reaction is 324 M/s.
The object is undergoing deceleration, as its speed is decreasing from 10 m/s to 3 m/s. The acceleration is negative because it is in the opposite direction of its initial velocity.
Time. 3 milliseconds
v = 3 km / 15 min = 3 km / 0.25 hr = 3 km x 4 (1/hr) = 12 km/hr The answer is 12 km/hr. v = 3 km / 15 min = 3000 m / 900 s = 30 m / 9 s = 10 m / 3 s = 3.3333 m/s The answer is 3.333 m/s.
3 m/s/s or 3 m/s^2a = (vf-fi)/(delta t), where a = acceleration, vf = final velocity, vi = initial velocity, and delta t = time interval. vf = 12 m/s, vi = 9.6 m/s, and delta t = 0.8 sPlug the known values into the equation and solve for acceleration.a=(12 m/s - 9.6 m/s)/(0.8 s) = 3 m/s/s or 3 m/s^2
"3 m/s north" is an example of a vector quantity, indicating both magnitude (3m/s) and direction (north).