It is: 3*(4+12) = 48
128
The product of 4 and 3 is (4 \times 3 = 12). The sum of 4 and 3 is (4 + 3 = 7). To find how much greater the product is than the sum, we subtract the sum from the product: (12 - 7 = 5). Therefore, the product is 5 greater than the sum.
3(x+4) is The equation. Distribute the 3, 3x+12, Theres your answer.
Two integers that have a sum of -7 and a product of 12 are -3 and -4.
4 cubed = 4 times 4 times 4 =64 12 + 64 = 76
128
The product of 4 and 3 is (4 \times 3 = 12). The sum of 4 and 3 is (4 + 3 = 7). To find how much greater the product is than the sum, we subtract the sum from the product: (12 - 7 = 5). Therefore, the product is 5 greater than the sum.
12, because 1 + 2 = 3, and 3 x 4 = 12.
4 [ 3 (x-6) ] = 12 4 [ 3x -18 ] = 12 12x - 72 = 12 12x = 84 x = 7
3(x+4) is The equation. Distribute the 3, 3x+12, Theres your answer.
Two integers that have a sum of -7 and a product of 12 are -3 and -4.
4 cubed = 4 times 4 times 4 =64 12 + 64 = 76
All multiples of 12 are also multiples of 6 and they all can be written as the sum of nine numbers.
1/3 + 3/4 = 4/12 + 9/12 = 13/12 = 1 and 1/12
3 times 4 = 3× 4 = 12 is the answer.
3x4? Well, 3x4 is basically 3+3+3+3 or 4+4+4. 4+4+4=12 3+3+3+3=12 Basically, 3x4 equals to 12.
2/3 + 1/4 = 8/12 + 3/12 = 11/12