15/4 x 8/3 = 120/12 = 10
No, it is 3:Factors of 12: 1, 2, 3, 4, 6, 12Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30Factors of 15: 1, 3, 5, 15GCF (12, 24, 30, 15) = 3
1, 2, 3, 4, 6, 12 1, 3, 5, 15 1, 2, 4, 7, 14, 28
no 4 is not a factor of 15 because 4 times 3 is 12 and 4 times 5 is 20
3 is the greatest number which divides 9, 12 and 15.Factors of 9: 1, 3 and 9.Factors of 12: 1, 2, 3, 4, 6 and 12.Factors of 15: 1, 3, 5 and 15.So, G.C.F. is 3.
12 and 3
15
It is: 3*(4+12) = 48
Two integers that have a sum of -7 and a product of 12 are -3 and -4.
25
The product of 4 and 3 is (4 \times 3 = 12). The sum of 4 and 3 is (4 + 3 = 7). To find how much greater the product is than the sum, we subtract the sum from the product: (12 - 7 = 5). Therefore, the product is 5 greater than the sum.
There are 59 possible sets of 4 factors and I am certainly not prepared to list them all.2, 3, 4, 12 has the smallest sum (21) in the required range.4, 5, 10, 15 has the largest sum (34) in the required range.There are 59 possible sets of 4 factors and I am certainly not prepared to list them all.2, 3, 4, 12 has the smallest sum (21) in the required range.4, 5, 10, 15 has the largest sum (34) in the required range.There are 59 possible sets of 4 factors and I am certainly not prepared to list them all.2, 3, 4, 12 has the smallest sum (21) in the required range.4, 5, 10, 15 has the largest sum (34) in the required range.There are 59 possible sets of 4 factors and I am certainly not prepared to list them all.2, 3, 4, 12 has the smallest sum (21) in the required range.4, 5, 10, 15 has the largest sum (34) in the required range.
1/3 + 3/4 = 4/12 + 9/12 = 13/12 = 1 and 1/12
1 + 14 2 + 13 3 + 12 4 + 11 5 + 10 6 + 9 7 + 8
3.75
2/3 + 1/4 = 8/12 + 3/12 = 11/12
box 1. 8 1 6 3 5 7 4 9 2 sum: 15 box 2. 1 15 14 4 12 6 7 9 8 10 11 5 13 3 2 16 magic sum: 34 box 3. 3 17 16 6 14 8 9 11 10 12 13 7 15 5 4 18 magic sum: 42