Write down both equations (I'll label them (1) and (2)):
(1) a = 3b - 4
(2) a + b = 16
Pass b to the left side of the equation (1):
(1) a - 3b = -4
(2) a + b = 16
Multiply (1) by -1:
(1) -a + 3b = 4
(2) a + b = 16
Add down both equations:
-a + 3b + a + b = 4 + 16
4b = 20
b = 5
Replace b in (2):
a + 5 = 16
a = 11
(x+7)2+(y+5)2 = 16 Centre of circle: (-7, -5) Radius: 4
It is 112
The answer is 64.
It equals 113.
The answer is 144. The compound operator for (a) and (b) in each pair is a * (a+b). For 9 and 7, this is 9 x (9+7) = 9 x 16 = 144.
16
The solutions are: x = -2 and y = 4
(x, y) = (3, 2)
(x+7)2+(y+5)2 = 16 Centre of circle: (-7, -5) Radius: 4
I think this means (x+7)squared + (y-5)squared =4squared, which represents a circle centred at -7,+5
2y = 4x - 16 5y = 4x + 8 Subtract the first equation from the second: 3y = 24 so that y = 8 Substitute this into the first equation: 16 = 4x - 16 ie 32 = 4x so that x = 8 So the solution is (8, 8)
2x + 4y = 16 <=> 2x + 4y - 16 = 0 2x - 4y = 0 2x - 4y = 2x + 4y - 16 -8y = -16 y = 2 Substituting the known value for y in either of the original equations enables x to be determined. 2x + (4*2) = 16 : 2x = 16 - 8 : x2x = 8 : x = 4 2x - (4*2) = 0 : 2x - 8 = 0 : 2x = 8 : x = 4. The ordered pair satisfying both equations is (4,2)
The center of the circle is at (-7, 5)
96
It is 112
It is the property that equals plus equals are equals.
The answer is 64.