It is an algebraic expression because it does not contain an equality sign.
Assuming "y3x 6" is "y=3x+6"The range of 3x+6 is -inf < y < inf.Proof below, a little technicallim(x -> inf)(3x+6)=+inflim(x -> - inf)(3x+6)=-infTherefore, the range is -inf < y < inf.
The equation you provided, "y3x - 11," appears to be incorrectly formatted. If you meant to write the equation in the form ( y = 3x - 11 ), then the y-intercept can be found by setting ( x = 0 ). Substituting ( x = 0 ) gives ( y = -11 ), so the y-intercept is -11. If the equation is different, please clarify for an accurate answer.
If you mean: y = 3x+2 then the parallel line will be y = 3x-3
If you mean: y = 3x+2 then the slope is 3 and the y intercept is 2
Without an equality sign it is not an equation but if you mean y = 3x-1 then it is a straight line equation
That depends is it 3x + or - 9?
Assuming "y3x 6" is "y=3x+6"The range of 3x+6 is -inf < y < inf.Proof below, a little technicallim(x -> inf)(3x+6)=+inflim(x -> - inf)(3x+6)=-infTherefore, the range is -inf < y < inf.
YES I THINK SO y=3x is a linear equation
If you mean: y = 3x-14 then y = 3x+14 are parallel to each other
y=3x+2 so the gradient or slope is 3
If you mean: y = 3x+2 then the parallel line will be y = 3x-3
If you mean: y = 3x+2 then the slope is 3 and the y intercept is 2
Without an equality sign it is not an equation but if you mean y = 3x-1 then it is a straight line equation
If you mean: y = 3x-5 then the slope is 3 and the y intercept is -5
If you mean: y = 3x-5 then the slope is 3 and the y intercept is -5
The gradient of the given line is 2/3. Gradient of the perpendicular is -3/2 The equation, therefore, is y = -(3/2)x + 5 or 2y = -3x + 10 or 3x + 2y - 10 = 0
If you mean y = 3x-2 then it is a straight line equation whereas 3 is the slope and -2 is the y intercept