The gradient of the given line is 2/3. Gradient of the perpendicular is -3/2
The equation, therefore, is y = -(3/2)x + 5
or 2y = -3x + 10
or 3x + 2y - 10 = 0
-3x+9=y
Convert the equation 2y = 5x - 4 into standard form then y = 2.5x - 2. Two straight lines are perpendicular if the product of their gradients is -1. Let the equation of the perpendicular line by y = mx + b. Then, 2.5m = -1 : m = -1/2.5 The y intercept occurs when x = 0. Then -3 = 0 + bc : b = -3 The equation of the perpendicular line is y = -1/2.5x -3 or 5y = -2x -15
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Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
The slope intercept equation also called the y intercept equation. It isy=mx+b in which x and y are coordinates, m is the slope of the line, and b is the y-intercept. so b would be the y-coordinate that intersects the y-axis.
I need answer
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
There is no y-intercept or slope for this given equation, because its graph is a vertical line perpendicular to the x-axis.
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
-3x+9=y
Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.
If you mean: 3y=-x+9 then y=-1/3x+3 and the perpendicular equation is y=3x+6
Perpendicular would mean that the slope of both lines have to be the same. The slope of the given line is 2, so the equation of the other line is of the form y=2x+c with c some constant. Since it is given that the intercept of the second line is -2, we know that -2 = 0.x + c which gives us c = -2 Using this, we can see that the equation of the perpendicular line is y=2x-2
Convert the equation 2y = 5x - 4 into standard form then y = 2.5x - 2. Two straight lines are perpendicular if the product of their gradients is -1. Let the equation of the perpendicular line by y = mx + b. Then, 2.5m = -1 : m = -1/2.5 The y intercept occurs when x = 0. Then -3 = 0 + bc : b = -3 The equation of the perpendicular line is y = -1/2.5x -3 or 5y = -2x -15
If the x intercept is a and the y intercept is b, then the equation of the line is bx + ay = ab
Solve the line equation for "y", to get it in slope-intercept form. You can immediately read the slope from this equation.Divide -1 by (slope of this first line) to get the slope of the second line - the one perpendicular to the given line. Write an equation for any line with this slope.
y=(1/3)x+5