No. 3x plus 2x = 5x. 3x multiplied by 2x = 6x²
To solve the equation 6x plus 4-3x,first subtract 3x from 4 which leaves you with 1x. The equation now reads 6x plus 1x, which equals 7x. --- Actually, to simplify this, we have to keep the numbers multiplied with the variables from the plain numbers. The equation based on the question it this: 6X + 4 - 3X So there is a +6X a -3x and a +4. So we simplify by consolidating the numbers multiplied with the Xs. So 6X - 3X is 3X. So we have 3x + 4. There is no way to solve this since we have only part of it and no equal sign.
4x - 4 = 3x + 114x - 3x = 11 + 4x = 15
(6-4x)(x-2)+3x =6x-12-4x+8x+3x =5x-4
9x2 + 24xy + 16y2 = 9x2 + 12xy + 12xy + 16y2 = 3x(3x + 4y) + 4y(3x + 4y) = (3x + 4y)*(3x + 4y) = (3x + 4y)2
It is: (3x-4)(3x+4) is the difference of two squares
Let the number be x: 2(2x+4) = 3x+4 4x+8 = 3x+4 4x-3x = 4-8 x = -4
So, we have 3x = 4 for some number x. We will solve for x. 3x = 4 (1/3)*(3x) = (1/3)*(4) [multiplied by (1/3) on both sides] x = 4/3
No. 3x plus 2x = 5x. 3x multiplied by 2x = 6x²
To solve the equation 6x plus 4-3x,first subtract 3x from 4 which leaves you with 1x. The equation now reads 6x plus 1x, which equals 7x. --- Actually, to simplify this, we have to keep the numbers multiplied with the variables from the plain numbers. The equation based on the question it this: 6X + 4 - 3X So there is a +6X a -3x and a +4. So we simplify by consolidating the numbers multiplied with the Xs. So 6X - 3X is 3X. So we have 3x + 4. There is no way to solve this since we have only part of it and no equal sign.
4x - 4 = 3x + 114x - 3x = 11 + 4x = 15
(6-4x)(x-2)+3x =6x-12-4x+8x+3x =5x-4
9x2 + 24xy + 16y2 = 9x2 + 12xy + 12xy + 16y2 = 3x(3x + 4y) + 4y(3x + 4y) = (3x + 4y)*(3x + 4y) = (3x + 4y)2
To find the product of (x+4) and (x^2-3x+2), you need to distribute each term in the first expression to each term in the second expression. This results in x*(x^2-3x+2) + 4*(x^2-3x+2). Simplifying further, you get x^3-3x^2+2x + 4x^2-12x+8. Combining like terms gives you the final answer: x^3+x^2-10x+8.
10x + 4 = 3x + 9Subtract 3x from each side of the equation:7x + 4 = 9Subtract 4 from each side:7x = 5Divide each side by 7:x =5/7
y = 12. It's the transitive property. y = 12 = 3x.
3x^5 If these are 5 of 3x multiplied together the it must be (3x)^5 =3^5 times x^5