3x+5<x+11 3x<6 x<2
If 3x - 1 = 11 what is the value of x 2 + x?
3x-1=11 x=4 x^2+x=20
2x + 3 + 3x = x + 11 5x + 3 = x + 11 4x + 3 = 11 4x = 8 x = (8/4) x = 2
3
3x+5<x+11 3x<6 x<2
If 3x - 1 = 11 what is the value of x 2 + x?
3x-1=11 x=4 x^2+x=20
When x = 2, 3x + 5 = 11.
It is equivalent to: 3x+6+5 = 3x+11
3
2x + 3 + 3x = x + 11 5x + 3 = x + 11 4x + 3 = 11 4x = 8 x = (8/4) x = 2
- If 3X - 1 = 11, what is the value of X^2 + X?
(4x^4 −5x^3 +6x+11)−?=x^4 −x^3 −x^2 −3x+2
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
3x + 11 = x + 3 2x = -8 x = -4
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)