3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
If 3x - 1 = 11 what is the value of x 2 + x?
x^2 + 3x + 7 = 6x + 18 x^2 - 3x - 11 = 0
7x - 2 = 4x + 9 3x - 2 = 9 3x = 11 x = 11/3
3x + 2 = 3x + 6 This is not possible.
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
If 3x - 1 = 11 what is the value of x 2 + x?
x^2 + 3x + 7 = 6x + 18 x^2 - 3x - 11 = 0
7x - 2 = 4x + 9 3x - 2 = 9 3x = 11 x = 11/3
At x = 3, the value of F(x) = 3x + 2 is the value 11, which graphs to the point (3, 11).
3x + 2 = 3x + 6 This is not possible.
x = 5, y = -1
- If 3X - 1 = 11, what is the value of X^2 + X?
3x-1=11 x=4 x^2+x=20
Your answer can be solved by rewriting the equation in point-intercept notation. * -3x + 2y = 11 * 2y = 3x + 11 * y = (3x+11)/2 That line lists all of the possible answers.
(2, -1)
Their graphs are.