3
3x² + 10x = 8 Rewrite as: 3x² + 10x - 8 = 0 The only way to get 3x² is 3x and x (3x + -- ) (x + --) The factors of 8 are {1 2 4 8} so the answers must be a pair of them. With 4 factors, and a negative sign (the -8), there are only 8 ways this can be written: (3x + 1)(x - 8) = 3x² - 23x - 8 (3x + 2)(x - 4) = 3x² -10x - 8 (almost) (3x + 4 )(x - 2) = 3x² - 8x - 8 (3x + 8)(x - 1) = 3x² +5x - 8 (3x - 1)(x + 8) = 3x² +23x - 8 (3x - 2)(x + 4) = 3x² + 10x -8 ◄ Success! (3x - 4)(x + 2) = 3x² +2x - 8 (3x - 8)(x + 1) = 3x² -5x - 8 Trial and error, error, error, is the key to this kind of problem. Seeing the -10x early can point you to see that maybe changing the signs can work. ■
3x + 8 = 8 Therefore, 3x = 0 x = 0/3 x = 0
3x - x = 3*8 - 8 = 24 - 8 = 16
3x = x+8 so 3x-x = 8 hence 2x = 8 and so x = 4
IF 3X-1=11, WHAT IS THE VALUE OF X 2 + X?
2x+x2x = x+xso 2x+x isx+x+x = 3x
-if3X-1=11,what is the value of X^2+X?
3
3x² + 10x = 8 Rewrite as: 3x² + 10x - 8 = 0 The only way to get 3x² is 3x and x (3x + -- ) (x + --) The factors of 8 are {1 2 4 8} so the answers must be a pair of them. With 4 factors, and a negative sign (the -8), there are only 8 ways this can be written: (3x + 1)(x - 8) = 3x² - 23x - 8 (3x + 2)(x - 4) = 3x² -10x - 8 (almost) (3x + 4 )(x - 2) = 3x² - 8x - 8 (3x + 8)(x - 1) = 3x² +5x - 8 (3x - 1)(x + 8) = 3x² +23x - 8 (3x - 2)(x + 4) = 3x² + 10x -8 ◄ Success! (3x - 4)(x + 2) = 3x² +2x - 8 (3x - 8)(x + 1) = 3x² -5x - 8 Trial and error, error, error, is the key to this kind of problem. Seeing the -10x early can point you to see that maybe changing the signs can work. ■
3x + 8 = 8 Therefore, 3x = 0 x = 0/3 x = 0
3x + x + 8 = 204x + 8 = 204x = 12x = 3
3x - x = 3*8 - 8 = 24 - 8 = 16
3x = x+8 so 3x-x = 8 hence 2x = 8 and so x = 4
If x equals 8, then 3x equals 24. 24-x would equal 16.
3x + 8 = 20 3x = 20 - 8 3x = 12 3x = 12/3 x = 4
If you mean: y = x+4 and y = 3x+8 then x = -2 and y = 2