It is two terms of an algebraic expression
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3y2 - 2y + 6xy - 4x = y(3y - 2) + 2x(3y - 2) = (y + 2x)*(3y - 2)
All six of them
I understand this to be y3. Then the derivative is 3y2. If y is considered a so-called 'implicit function' of x then the derivative might be written 3y2 dy/dx.
Yes. It is like having a-b, which is a+(-b), which is -b+a, so 3-2y = 3+(-2y) = -2y+3
(3y - 2)(y - 4)