It is equivalent to: 14y+112
2y - 8 = 14y + 64 Subtract 2y from both sides: -8 = 12y + 64 Subtract 64 from both sides: -72 = 12y or 12y = -72 Divide both sides by 12: y = -6
8y+6y is 14y
(x+1)(x+8)
8(x + 1)
It is equivalent to: 14y+112
it's MINUS 182.5
Since 3y2 can evenly divide 24y3, 3y2 must be the greatest common factor, since the greatest common factor cannot be larger than the smaller of the two numbers. But, we can also look at a factorization of both numbers. We can tell that 3y2 = 3 x y2. We can tell that 24y3 = 3 x 8 x y3 = 3 x 23 x y2 x y. These numbers have in common 3 and y2, so 3y2 is the greatest common factor.
2y - 8 = 14y + 64 Subtract 2y from both sides: -8 = 12y + 64 Subtract 64 from both sides: -72 = 12y or 12y = -72 Divide both sides by 12: y = -6
The GCF is 8. 8(m + n)
8y+6y is 14y
(x + 8)(x + 1)
(x+1)(x+8)
8(x + 1)
(8 + 3v)(8 + 3v) or (8 + 3v)2
Equation: x^2 + y^2 +10x -14y +10 = 0 Completing the squares: (x+5)^2 + (y-7) -25-49 +10 = 0 So: (x+5)^2 + (y-7) = 64 Therfore the circle's centre is at (-5, 7) and its radius is 8
(x + 5)(x + 8)