3y - 7 + y + 27 = 6y + 20 - 4y Collect terms: 4y + 20 = 2y + 20 Subtract 20 4y = 2y The only way that can happen is if y = 0
2x + 3y = 17 3x + 4y = 24 (2x + 3x) + (3y + 4y) = (17 + 24) 5x + 7y = 41
(-1,-2)
4y + 7 < 3y + 9 4y - 3y < 9 - 7 y < 2
6x - 4y
3y - 7 + y + 27 = 6y + 20 - 4y Collect terms: 4y + 20 = 2y + 20 Subtract 20 4y = 2y The only way that can happen is if y = 0
2x + 3y = 17 3x + 4y = 24 (2x + 3x) + (3y + 4y) = (17 + 24) 5x + 7y = 41
4y + 4 = 3y - 5 y = -9
(9,2)
6x plus 4y
(-1,-2)
4y + 7 < 3y + 9 4y - 3y < 9 - 7 y < 2
6x - 4y
4y -5
If y + 3y + 10 = 70, then 4y + 10 = 70, and 4y = 60. We then find that y = 60/4 = 15.
x = 5, y = -1
I don't know whether it's y^2-3y+2+3y-4y-5 or 2y-3y+2+3y-4y-5, so I'll do both.y^2-3y+2+3y-4y-5y^2+(-3y+3y-4y)+(2-5); group them togethery^2+(-4y)+(-3)y2-4y-3OR2y-3y+2+3y-4y-5(2y-3y+3y-4y)+(2-5); group them together(-2y)+(-3)-2y-3