If 3y = 12, 2y = 8
3y plus 6x = 2
x=2 y=7 5x+3y= 5 7 x 2 x 3 ____ _____ 10 21 21 + 10 _______ 31
3y + 4z + 12y = 3y -3y -3y ------------------------- 4z + 12y = 0 divide everything by 4 z + 3y = 0 -3y -3y z = -3y
5x + (3y-x) + (10-2y) = 5x + 3y - x + 10 -2y = 5x - x + 3y - 2y + 10 = 4x + y +10
it is equal to 6y plus y
2(-2)-3y=6 which is equal to -4 -3y = 6 which is equal to -3y = 10 which is equal to y = -(10 / 3) = -3.333...
(3y + 5)(y - 2)
If 5x plus 3y equals 13, the x equals 2 and y equals 1. This is because 5x2=10 and 3x1=3, and 10+3=13.
y=-39
(2,7)
That depends on what the value of x is.
5x+3y
4.34684352143
10-y=2y+3 10-3=2y+y 7=3y 7/3=y
4y + 7 - y = 10 + 3y My next step is to combine the y's on the left, 3y + 7 = 10 + 3y If I then subtract 3y from both sides I obtain 7 = 10 which is not a true statement. Hence, the equation that you presented is invalid.
-2x plus 3y equals 1