400ml x B = 1000ml bit of algebra solves this.
I take it ur doing this for a chemistry class possibly or probably somewhere in Florida... I had the same prob now there are two ways to solve this: easy and absolute First L is not SOME stuff it is A measurement of volume - so is cm3 but not cm (distance) or cm2 (area) NOTE humans cannot understand cm4 because we live in the 3rd dimension and time. Easy: 1cm3=1mL .*. 400cm3=400mL=40cL=4dL=.4L Absolute: even I don't fully understand it!
1000 ml = 1 litre Therefore there are 2.5 (or 21/2) batches of 400 ml in 1 litre. (As 2.5 x 400 = 1000).
------------- / \ / \ l l l l \ / \ / -------------- somthing like that :)
1
1000mL = 1L For every 1000mL we have 1 L. So- 400mL x 1L/1000mL = 0.4L
1 L = 1,000 ml . . 6 L = 6,000 ml 6,000/400 = 15 times
1000 millilitres = 1 litre so 400 ml = 0.4 L. Simple!
To express 400ml as a fraction of 1 liter, you can write it as \frac{400}{1000} 1000 400 since there are 1000 milliliters in a liter. Simplifying the fraction gives \frac{2}{5} 5 2 . Therefore, 400ml is equivalent to \frac{2}{5} 5 2 of 1 liter.
2/5 of 1L = 400ML
The weight of 400ml of milk can vary depending on the specific type of milk, but on average, 400ml of milk weighs approximately 400 grams.
There are 1.69 cups in 400ml of water.
400mL is 13.5 (13.5256) fluid ounces.
1L = approx 1Kg therefore 1ml = 1g so 400ml = 400g
We first calculate the amount, in moles, of NaCl that we will need.Amount of NaCl needed = 0.24 x 400/100 = 0.096mol. Mass of NaCl needed = (23.0 + 35.5) x 0.096 = 5.616g So to produce 400ml of 0.24M NaCl solution, accurately add 5.616 grams of NaCl to 400ml of deionised water.
5/4
To calculate the mass of KOH needed to make 400mL of 725 M KOH solution, you would use the formula: mass = volume (in L) * molarity * molar mass First, convert the volume from mL to L (400mL = 0.4 L). Then plug in the values for volume (0.4 L), molarity (725 M), and the molar mass of KOH (39.10 g/mol) to find the mass of KOH needed. mass = 0.4 L * 725 mol/L * 56.11 g/mol ≈ 131.78 grams.