The product of 47, 29, and 11 is 15,113. You can calculate this by first multiplying 47 and 29 to get 1,363, and then multiplying that result by 11, which equals 15,113.
I believe it is 4089xy... i think...
I am assuming the question is to factor this problem? 5x2 + 29x - 6 (5x - 1)(x + 6)
29x
(3x)/8 + (5x)/6 = 29 (* means multiply, and x is the number) > (3*3x)/(8*3) + (4*5x)/(6*4) = 29 > (9x)/24 + (20x)/24 = 29 > (29x)/24 = 29 > 24(29x)/24 = 29*24 > 29x = 696 > (29x)/29 = 696/29 > x = 24
(7x-3)(2x+5) 14x2 + 29x - 15, write 29x = 35x - 6x = 14x2 - 6x + 35x - 15 = (14x2 - 6x) + (35x - 15) = 2x(7x - 3) + 5(7x - 3) = (7x-3)(2x+5)
15x + 32x - 28 = 47x - 28 = (√47x)2 - (√28)2 = (√47x)2 - (2√7)2 = (√47x - 2√7)(√47x + 2√7)
It is -29x + 3, exactly as in the question.
2x + -94x - 29x-121x
10x2 - 29x = 21 10x2 - 29x - 21 = 0 so x = -0.6 or x = 3.5
47x
I believe it is 4089xy... i think...
47x =4606
(2x+5)(7x-3)=14x2 +29x-15
4x2+29x-24 = (4x-3)(x+8) when factored
I am assuming the question is to factor this problem? 5x2 + 29x - 6 (5x - 1)(x + 6)
== 29x blank== 87 ==
29x