15x + 32x - 28 = 47x - 28 = (√47x)2 - (√28)2 = (√47x)2 - (2√7)2 = (√47x - 2√7)(√47x + 2√7)
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Yes, because the equation is linear, there is only one solution:4x - 3 = 12 +2x4x - 2x = 12 + 32x = 15x = 7.5There is no other solution
4x^2 + 32x + 64 = 4(x^2 + 8x + 16) = 4(x + 4)^2 = 4(x + 4)(x + 4)
64
Note that 16X is a factor of 32X [16X times 2 is 32X]. So now whether it's (32X)^4 or 32 times (X^4), that will still be the LCM, so the answer is 32X to the 4th power, just as it's stated in the question.
It could be a linear equation in two variables. A single linear equation in two variables cannot be solved.