15x + 32x - 28 = 47x - 28 = (√47x)2 - (√28)2 = (√47x)2 - (2√7)2 = (√47x - 2√7)(√47x + 2√7)
Yes, because the equation is linear, there is only one solution:4x - 3 = 12 +2x4x - 2x = 12 + 32x = 15x = 7.5There is no other solution
4x^2 + 32x + 64 = 4(x^2 + 8x + 16) = 4(x + 4)^2 = 4(x + 4)(x + 4)
64
Note that 16X is a factor of 32X [16X times 2 is 32X]. So now whether it's (32X)^4 or 32 times (X^4), that will still be the LCM, so the answer is 32X to the 4th power, just as it's stated in the question.
It could be a linear equation in two variables. A single linear equation in two variables cannot be solved.
48y - 32x
It is 6x(2x+5) when factored
The given quadratic expression can not be factored as a perfect square.
The expression (32x - 32x^2) can be factored as (32x(1 - x)). This represents a quadratic function, where the term (32x^2) indicates it opens downwards, and the factor (32) scales the function. The expression can be analyzed further to find its roots or maximum value, but in its current form, it is a simplified polynomial expression.
4x + 32x + 9 = 36x + 9
32x + 8 – 34x
If 32X + 53 = 501, then 32X = 448, and X = 448/32 = 14.
35x + 10
That's pretty easy. Just add the like terms (2x and 32x) and keep the 3. You get 34x plus 3.
Isolating xx = (6+6)/32x = 0.375
-16x2 + x + 8 = -1/64(32x - 1 - √513)(32x - 1 + √513)
Yes, because the equation is linear, there is only one solution:4x - 3 = 12 +2x4x - 2x = 12 + 32x = 15x = 7.5There is no other solution