4.083333 repeating
(1/6)+(1/12)=(2/12)+(1/12)=(3/12)=(1/4)=0.25
0.25 3/12 = 1/4 = 0.25
0.3333 repeating. 4/12 reduces down to 1/3. This decimal will go on forever. An easy way to write it is just .3, with a horizontal line over it, representing the 3 goes on forever.4/12 = 1/3 = 0.33 (recurring).
.3 repeating Or 1/3
4/33 as a decimal is 0.'12' recurring '12'
4/12 = 1/3 = 0.33... (recurring).
15/12 = 1 3/12 = 1 1/4 = 1.25
(1/6)+(1/12)=(2/12)+(1/12)=(3/12)=(1/4)=0.25
0.25 3/12 = 1/4 = 0.25
0.3333 repeating. 4/12 reduces down to 1/3. This decimal will go on forever. An easy way to write it is just .3, with a horizontal line over it, representing the 3 goes on forever.4/12 = 1/3 = 0.33 (recurring).
.3 repeating Or 1/3
4/12 - 6/12 = -2/12 or -1/6. Expressed as a decimal, this is equal to -0.16 recurring (that is, -0.16666...)
4/33 as a decimal is 0.'12' recurring '12'
An identity (in decimal arithmetic). 12 + 4/8 = 12 + 1/2 = 12 + 0.5 = 12.5
4/12 as a decimal is 0.'3' recurring '3'
To subtract 11 in base 2 from 100 in base 2, you first convert both numbers to decimal. 100 in base 2 is equal to 4 in decimal (12^2 + 02^1 + 02^0). Similarly, 11 in base 2 is equal to 3 in decimal (12^1 + 12^0). Subtracting 3 from 4 in decimal gives you 1 in decimal, which is equal to 1 in binary (12^0). Therefore, 100 in base 2 minus 11 in base 2 equals 1 in base 2.
1 1/1