To evaluate the expression (4c , 1 - (5 , 2c)), we first need to clarify the notation. Assuming (c) represents a variable and (n , k) represents the binomial coefficient "n choose k," we have (4c , 1 = 4) and (5 , 2c = 10). Therefore, the expression simplifies to (4 - 10), which equals (-6).
4c+1-5+2c = 6c-4.
To simplify the expression (4c + 1 - (5 - 2c)), first distribute the negative sign: (4c + 1 - 5 + 2c). Next, combine like terms: (4c + 2c + 1 - 5 = 6c - 4). Thus, the simplified expression is (6c - 4).
6c-4c =2c
12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c
4c2 + 5c + 2c = 4c2 + 7c = c(4c + 7)
4c+1-5+2c = 6c-4.
To simplify the expression (4c + 1 - (5 - 2c)), first distribute the negative sign: (4c + 1 - 5 + 2c). Next, combine like terms: (4c + 2c + 1 - 5 = 6c - 4). Thus, the simplified expression is (6c - 4).
8c2-26c+15 8c2-6c-20c+15 2c(4c-3)+5(-4c+3) (2c-5)(4c-3)
4c-7 = 2c+11 4c-2c = 11+7 2c = 18 c = 9
2c+4c-3c+5c = 6c +2c = 8c
6c-4c =2c
tell me time table of ME 2C drawing, ME 3C and 4C tell me time table of ME 2C drawing, ME 3C and 4C
12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c
4c2 + 5c + 2c = 4c2 + 7c = c(4c + 7)
6c-18=4c Why can rearrange this and simplify to 2c=18, which means that c = 9
its hard sorry
4c^2-12c+9 is a trinomial because it is in the form of ax^2 + bx + c. In this case, the trinomial is a perfect square trinomial. 4c^2-12c+9 =(2c-3)(2c-3) =(2c-3)^2