0
Add your answer:
Earn +20 pts
What is the perpendicular bisector equation of the line joined by the points of p q and 7p 3q on the Cartesian plane?
Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0
What is the relation of the forms y equals Psinx plus Qcosx and y equals Asin of x plus c?
A = Root (Q squared plus P squared) C = 90 + tan inverse P/Q ... I think lol just worked it out just now =w=
What is the integral of the derivative with respect to x of f divided by the quantity p squared plus q squared f squared with respect to x where f is a function of x and p and q are constants?
∫ f'(x)/(p2 + q2f(x)2) dx = [1/(pq)]arctan(qf(x)/p)
What does q Squared equal?
It equals the value of 'q', multiplied by itself.
What are P and Q if Square of P plus square of Q equals 123456789 in some order?
If p and q are both squared, then they would both be even numbers, and the sum of them couldn't end in 9, so not possible with whole numbers
What is the perpendicular bisector equation of the line joined by the points of p q and 7p 3q on the Cartesian plane?
Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0
What is the perpendicular bisector equation of a line segment with endpoints of p q and 7p 3q?
A line with slope m has a perpendicular with slope m' such that:mm' = -1→ m' = -1/mThe line segment with endpoints (p, q) and (7p, 3q) has slope:slope = change in y / change in x→ m = (3q - q)/(7p - p) = 2q/6p = q/3p→ m' = -1/m = -1/(q/3p) = -3p/qThe perpendicular bisector goes through the midpoint of the line segment which is at the mean average of the endpoints:midpoint = ((p + 7p)/2, (q + 3q)/2) = (8p/2, 4q/2) = (4p, 2q)A line through a point (X, Y) with slope M has equation:y - Y = M(x - x)→ perpendicular bisector of line segment (p, q) to (7p, 3q) has equation:y - 2q = -3p/q(x - 4p)→ y = -3px/q + 12p² + 2q→ qy = 12p²q + 2q² - 3pxAnother Answer: qy =-3px +12p^2 +2q^2
Q squared plus 20 q plus c?
I'm not exactly sure what you mean by this, but if you'd like to know how to do this in C here: q ^ 2 + 20 q + c
What is 12p plus 19q plus p - 5q - 3p?
To simplify the expression 12p + 19q + p - 5q - 3p, we first combine like terms. Combining the p terms, we have 12p + p - 3p, which simplifies to 10p. Combining the q terms, we have 19q - 5q, which simplifies to 14q. Therefore, the simplified expression is 10p + 14q.
What is the relation of the forms y equals Psinx plus Qcosx and y equals Asin of x plus c?
A = Root (Q squared plus P squared) C = 90 + tan inverse P/Q ... I think lol just worked it out just now =w=
When was Q-Squared created?
Q-Squared was created in 1994-07.
What is 4 times the sum of q and p?
4(p + q), or 4p + 4q
What is the ISBN of Q-Squared?
The ISBN of Q-Squared is 0-671-89151-0.
How do you solve q squared plus 16q equals 0?
By factoring. q2 + 16q = 0 q (q + 16) = 0 Now, either q = 0, or q + 16 = 0. Solve those two equations to get the solution.
What is sec squared theta minus tan squared theta?
1 - sin2(q) = cos2(q)dividing through by cos2(q),sec2(q) - tan2(q) = 1
What is the integral of the derivative with respect to x of f divided by the quantity p squared plus q squared f squared with respect to x where f is a function of x and p and q are constants?
∫ f'(x)/(p2 + q2f(x)2) dx = [1/(pq)]arctan(qf(x)/p)
What does q Squared equal?
It equals the value of 'q', multiplied by itself.
