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What is the perpendicular bisector equation of the line joined by the points of p q and 7p 3q on the Cartesian plane?
Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0
What is the relation of the forms y equals Psinx plus Qcosx and y equals Asin of x plus c?
A = Root (Q squared plus P squared) C = 90 + tan inverse P/Q ... I think lol just worked it out just now =w=
What is the integral of the derivative with respect to x of f divided by the quantity p squared plus q squared f squared with respect to x where f is a function of x and p and q are constants?
∫ f'(x)/(p2 + q2f(x)2) dx = [1/(pq)]arctan(qf(x)/p)
What are P and Q if Square of P plus square of Q equals 123456789 in some order?
If p and q are both squared, then they would both be even numbers, and the sum of them couldn't end in 9, so not possible with whole numbers
What does q Squared equal?
It equals the value of 'q', multiplied by itself.
What is the perpendicular bisector equation of the line joined by the points of p q and 7p 3q on the Cartesian plane?
Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0
What is the perpendicular bisector equation of a line segment with endpoints of p q and 7p 3q?
A line with slope m has a perpendicular with slope m' such that:mm' = -1→ m' = -1/mThe line segment with endpoints (p, q) and (7p, 3q) has slope:slope = change in y / change in x→ m = (3q - q)/(7p - p) = 2q/6p = q/3p→ m' = -1/m = -1/(q/3p) = -3p/qThe perpendicular bisector goes through the midpoint of the line segment which is at the mean average of the endpoints:midpoint = ((p + 7p)/2, (q + 3q)/2) = (8p/2, 4q/2) = (4p, 2q)A line through a point (X, Y) with slope M has equation:y - Y = M(x - x)→ perpendicular bisector of line segment (p, q) to (7p, 3q) has equation:y - 2q = -3p/q(x - 4p)→ y = -3px/q + 12p² + 2q→ qy = 12p²q + 2q² - 3pxAnother Answer: qy =-3px +12p^2 +2q^2
What is 12p plus 19q plus p - 5q - 3p?
To simplify the expression 12p + 19q + p - 5q - 3p, we first combine like terms. Combining the p terms, we have 12p + p - 3p, which simplifies to 10p. Combining the q terms, we have 19q - 5q, which simplifies to 14q. Therefore, the simplified expression is 10p + 14q.
Q squared plus 20 q plus c?
I'm not exactly sure what you mean by this, but if you'd like to know how to do this in C here: q ^ 2 + 20 q + c
What is the relation of the forms y equals Psinx plus Qcosx and y equals Asin of x plus c?
A = Root (Q squared plus P squared) C = 90 + tan inverse P/Q ... I think lol just worked it out just now =w=
When was Q-Squared created?
Q-Squared was created in 1994-07.
What is 4 times the sum of q and p?
4(p + q), or 4p + 4q
What is the ISBN of Q-Squared?
The ISBN of Q-Squared is 0-671-89151-0.
How do you solve q squared plus 16q equals 0?
By factoring. q2 + 16q = 0 q (q + 16) = 0 Now, either q = 0, or q + 16 = 0. Solve those two equations to get the solution.
What is sec squared theta minus tan squared theta?
1 - sin2(q) = cos2(q)dividing through by cos2(q),sec2(q) - tan2(q) = 1
What is the integral of the derivative with respect to x of f divided by the quantity p squared plus q squared f squared with respect to x where f is a function of x and p and q are constants?
∫ f'(x)/(p2 + q2f(x)2) dx = [1/(pq)]arctan(qf(x)/p)
What does q Squared equal?
It equals the value of 'q', multiplied by itself.
